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2 years ago

Which of the following quantities is inversely proportional to the gravitational pull between two objects?

Physics

2 answers:

Contact [7]2 years ago

7 0

Answer:

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

I hope this helps a little bit

Ket [755]2 years ago

6 0

The correct Option is :

=》(C) The square of the distance that separates them

$f \: \: \dfrac{1}{ \alpha } \: \: r {}^{2}$

where,

f = gravitational force

r = distance between the objects

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The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I

erma4kov [3.2K]

Answer:

Part a)

$I_{end} = \frac{mL^2}{3}$

Part b)

$I_{edge} = \frac{2ma^2}{3}$

Explanation:

As we know that by parallel axis theorem we will have

$I_p = I_{cm} + Md^2$

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

$I = \frac{mL^2}{12}$

now if we need to find the inertia from its end then we will have

$I_{end} = I_{cm} + Md^2$

$I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2$

$I_{end} = \frac{mL^2}{3}$

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

$I = \frac{ma^2}{6}$

now if we need to find the inertia about an axis passing through its edge

$I_{edge} = I_{cm} + Md^2$

$I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2$

$I_{edge} = \frac{2ma^2}{3}$

7 0

3 years ago

What is the mass of a stone moving at a speed of 15 m/s and having a monument at 7.1 kg meters per second

adell [148]

Answer:

<h3>The answer is 0.47 kg</h3>

Explanation:

The mass of the object given it's momentum and velocity can be found by using the formula

$m = \frac{p}{v} \\$

where

p is the momentum

v is the velocity

We have

$m = \frac{7.1}{15} \\ = 0.4733333...$

We have the final answer as

Hope this helps you

4 0

2 years ago

B. Find the centripetal force needed to keep an 60.0 kg rider traveling in a circle in the ride.

schepotkina [342]

Answer:

loloololo

lol

Explanation:

lolloolololo

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2 years ago

George walks to a friend's house. He walks 850 meters north before he realizes he walked too far.

anyanavicka [17]

Answer:

Explanation:

In this problem we are expected to calculate the velocity of Georges movements.

Given data

Total distance covered by George= 850+250= 1100 meters

Time taken by George to cover the total distance= 25 seconds

We know that velocity is, v= distance/ time

Therefore substituting our data into the expression for velocity we have

v= 1100/ 25= 44 m/s

Hence the velocity in m/s is 44

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2 years ago

Special relativity can be used to study an object in which frame of reference? A. A frame of reference that has no change in vel

Georgia [21]

Answer:

gangster

Explanation:

sorrynsjajshdnqmanshsha

4 0

2 years ago

Read 2 more answers