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3 years ago

The picture below shows a man in Varanasi, India, resting on a bed of nails. Which principle about impact force

Physics

1 answer:

jasenka [17]3 years ago

7 0

Answer:

Since there are hundreds of nails, instead of puncturing your skin the nails actually support you.

Explanation:

If you step on the point of a nail, your foot exerts a tremendous amount of pressure on the nail's tiny point. As a result, the point can go straight through your foot. But a bed of nails has lots of points that are close together -- there's a lot of surface area for the body to cover. Hundreds of nails support the weight of your body instead of just one. Typically, your body doesn't exert enough pressure on any one nail for it to break the skin. You can even place a second bed on top of you and break a cinderblock on it. The resulting force is distributed over all of the nails, so you shouldn't be injured.

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When another driver passes you on the left, you must _________ until the vehicle passes?

Vlada [557]

Is there any answers option?

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3 years ago

A free negative charge released in an electric field will

SashulF [63]

Answer:

Will experience a force due to electric field.

Explanation:

When a free negative charge is released in an electric field it experiences a force due to the electric field in a direction opposite to the direction of the magnetic field.

According to Coulomb's law this force is mathematically given as:

$F=E.q$

and, electric field due to a charge is given as:

$E=\frac{1}{4\pi.\epsilon_0}.\frac{q}{r^2}$

where:

permittivity of free space $\epsilon_0=8.85\times 10^{-12}\ m^{-3}.kg^{-1}.s^4.A^2$

q = magnitude of charge

r = radial distance from the charge

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4 years ago

Can work be done on a system if there is no motion?

Minchanka [31]

Answer:

D) No, because of the way work is defined

Explanation:

The work done on an object is given by:

$W=Fd cos \theta$

where

F is the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and the displacement

From the formula, we observe that if there is no motion involved, then the displacement of the object is zero:

d = 0

As a result, the product in the formula is also zero, therefore the work done will be zero as well.

5 0

3 years ago

A U-tube is open to the atmosphere at both ends. Water is poured into the tube until the water column on the vertical sides of t

zmey [24]

Answer:

The value is $\Delta h = 0.003 \ m$

Explanation:

From the question we are told that

The height of the water is $h_1 = 10 \ cm = 0.10 \ m$

The density of oil is $\rho_o = 950 \ kg/m^3$

The height of oil is $h_2 = 6 \ cm = 0.06 \ m$

Given that both arms of the tube are open then the pressure on both side is the same

$P_a = P_b$

=> Here

$P_a = P_z + \rho_w * g * h$

where $\rho_w$ is the density of water with value $\rho_w = 1000 \ kg/m^3$

and $P_z$ is the atmospheric pressure

and

$P_b = P_z + \rho_o * g * h_2$

=> $P_z + \rho_w * g * h = P_z + \rho_o * g * h_2$

=> $\rho_w * h = \rho_o * h_2$

=> $h = \frac{950 * 0.06 }{1000}$

=> $h = 0.057 \ m$

The difference in height is evaluated as

$\Delta h = 0.06 - 0.057$

$\Delta h = 0.003 \ m$

6 0

3 years ago

A track star in the broad jump goes into the jump at 12 m/s and launches himself at 20° above the horizontal. How long is he in

emmainna [20.7K]

Explanation:

It is given that,

Initial speed of the broad jump, u = 12 m/s

It is launched at an angle of 20 degrees above the horizontal. Let t is the time for which the track star i in the air before returning to Earth. The motion of the track star in the broad jump can be treat as the projectile motion. The time of flight of the projectile is given by :

$t=\dfrac{2u\ sin\theta}{g}$

Putting all the values in above equation as :

$t=\dfrac{2\times 12\times \ sin(20)}{9.8}$

t = 0.837 seconds

So, the time for which the track star is in air is 0.837 seconds. Hence, this is the required solution.

3 0

3 years ago