Answer:
so the distance between two points are
![d = 0.246 \times 10^{-3} m](https://tex.z-dn.net/?f=d%20%3D%200.246%20%5Ctimes%2010%5E%7B-3%7D%20m)
Explanation:
Surface charge density of the charged plane is given as
![\sigma = 7.2 \mu C/m^2](https://tex.z-dn.net/?f=%5Csigma%20%3D%207.2%20%5Cmu%20C%2Fm%5E2)
now we have electric field due to charged planed is given as
![E = \frac{\sigma}{2\epsilon_0}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%5Cepsilon_0%7D)
now we have
![E = \frac{7.2 \times 10^{-6}}{2(8.85 \times 10^{-12})}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B7.2%20%5Ctimes%2010%5E%7B-6%7D%7D%7B2%288.85%20%5Ctimes%2010%5E%7B-12%7D%29%7D)
![E = 4.07 \times 10^5 N/C](https://tex.z-dn.net/?f=E%20%3D%204.07%20%5Ctimes%2010%5E5%20N%2FC)
now for the potential difference of 100 Volts we can have the relation as
![E.d = \Delta V](https://tex.z-dn.net/?f=E.d%20%3D%20%5CDelta%20V)
![4.07 \times 10^5 (d) = 100](https://tex.z-dn.net/?f=4.07%20%5Ctimes%2010%5E5%20%28d%29%20%3D%20100)
![d = \frac{100}{4.07 \times 10^5}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B100%7D%7B4.07%20%5Ctimes%2010%5E5%7D)
![d = 0.246 \times 10^{-3} m](https://tex.z-dn.net/?f=d%20%3D%200.246%20%5Ctimes%2010%5E%7B-3%7D%20m)
A - the objects are too small
GRAVITATIONAL FORCE IS EXPERIENCED BY ALL OBJECTS IN THE UNIVERSE ALL THE TIME. BUT THE ORDINARY OBJECTS YOU SEE EVERY DAY HAVE MASSES SO SMALL THAT THEIR ATTRACTION TOWARD EACH OTHER IS HARD TO DETECT. -https://www.ftsd.org/cms/lib6/MT01001165/Centricity/ModuleInstance/630/CHAPTER_2_NOTES_FOR_EIGHTH_GRADE_PHYSICAL_SCIENCE.pdf
The standard unit is KW/hr, = 1,000W/hr.
(85 + 60) = 145W.
You need to find its fraction of 1,000W., so (145/1000) = 0.145 KWH.
(0.145 x 10p) = 1.45p. per hr.
Answer:
yes it flows through flow paths.
Explanation:
Thermal energy is converted to radiative energy via molecular collisions and released as photons.