Question

Two objects that are not initially in thermal equilibrium are placed in close contact. After a while, the temperature of the coder object will rise the same amount that the hotter one drops. the temperature of each object will be the same. the thermal conductivity of each object will be the same. the specific heats of both objects will be equal. the temperature of the coder object will rise twice as much as the temperature of the hotter one drops

Answer 1

Answer:

If the temperature of  the colder object rises by the same amount as the temperature of the hotter object drops, then the specific heats of both objects will be equal.

Explanation:

If the temperature of  the colder object rises by the same amount as the temperature of the hotter object drops when the two objects of same mass are brought into contact, then their specific heat capacity is equal.

We can prove this by the equation of heat for the two bodies:

According to given condition,

$\Delta T_1=\Delta T_2$

$\frac{Q_1}{m_1.c_1} = \frac{Q_2}{m_2.c_2}$

when there is no heat loss from the system of two bodies then $Q_1=Q_2$

$\frac{1}{m.c_1} =\frac{1}{m.c_2}$

$\Rightarrow c_1=c_2$

• Thermal conductivity is ultimately affects the rate of heat transfer, however the bodies will attain their final temperature based upon their mass and their specific heat capacities.

The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:

• when the specific heat of the colder object is half the specific heat of the hotter object while mass is equal for both.

OR

• the mass of colder object is half the mass of the hotter object while their specific heat is same.