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3 years ago

Define the following terms: Internal energy

Physics

1 answer:

sergey [27]3 years ago

8 0

Answer and Explanation:

Internal Energy:

Internal energy associated to a system is the total amount of energy of a system excluding both the kinetic and potential energies as a whole for any external effects and is only accountable for any change in the energies of the system due to the internal order or states. It can be considered as that energy of the system essential to make it ready for any provided state.

Specific heat:

It is the specific amount of heat that is contained in a unit mass of any substance needed to bring about [tex]1^{\circ} rise in its temperature.

Entropy:

It can be defined as the degree of disorientation of the molecules or the extent of disorder of the system. It is the lack in thermal energy of the system to get converted into work (mechanical).

Temperature:

The measure of the heat intensity of a substance on a given standard scale.

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61 pts!!!!!!!!!!!!!!!!!!!

Olegator [25]

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3 years ago

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A small 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 10^3 N/C. If th

tensa zangetsu [6.8K]

Answer:

The net charge is $67.89 \mu C$

Solution:

As per the question:

Mass of the plastic bag, m = 12.0 g = $12.0\times 10^{-3}\ kg$

Magnitude of electric field, E = $10^{3}\ N/C$

Angle made by the string, $\theta = 30^{\circ}$

Now,

To calculate the net charge, Q on the ball:

Vertical component of the tension in the string, $T = Tcos\theta$

Horizontal component of the tension in the string, $T = Tsin\theta$

Now,

Balancing the forces in the x-direction:

$Tsin\theta = QE$

$Q = {Tsin\theta}{E}$ (1)

Balancing the forces in the y-direction:

$Tcos\theta = mg$

where

g = acceleration due to gravity = $9.8\ m/s^{2}$

Thus

$T = \frac{mg}{cos\theta }$

$T = \frac{12.0\times 10^{-3}\times 9.8}{cos30^{\circ}} = 0.1357\ N$

Use T = 0.1357 N in eqn (1):

$Q = {0.1357\times sin30^{\circ}}{10^{3}} = 6.789\times 10^{- 5}\ C$

$Q = 67.89\times 10^{- 5}\ C = 67.89\mu C$

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4 years ago

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mr_godi [17]

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3 years ago

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What happens when light runs into object

Paul [167]

Explanation:

It depends on the object, actually. If the object is transparent or somewhat clear, the the light will end up refracting, or bending, through those clear objects. It can also bounce off objects, too. But, with some objects, the light can be blocked, or absorbed.

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3 years ago

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You can also enter units that are combinations of other units. Keep in mind that you have to indicate the multiplication of unit

juin [17]

Answer:

98 N

Explanation:

Given that The weight of an object is the product of its mass, m, and the acceleration of gravity, g (where g=9.8 m/s2). Of an object’s mass is m=10. kg,

The parameters to be considered are

Mass m = 10 kg

Acceleration due to gravity = 9.8m/s^2

Weight W = mg

substitute mass m and acceleration due to gravity g into the formula above.

Weight = 10 × 9.8

Weight = 98 N

Therefore, the weight of the body or object is 98 N

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4 years ago