<em>mC: 12g/mol</em>
12g ------- 6,02·10²³ a.
6g --------- X
X = (6×<span>6,02·10²³)/12
</span><u>X = 3,01·10²³ atoms</u>
---->>> A :)
Applied force
Gravitational force
And Normal force
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
Explanation:
Balanced chemical equation for combustion of pentane C₅H₁₀:
C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)
to get integer numbers for the stoechiometric coefficients we multiply with 2:
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
where:
(l) - liquid
(g) - gas
Learn more about:
combustion of hydrocarbons
brainly.com/question/13691565
#learnwithBrainly
The answer is:
E per gram = 0.45 V
The explanation:
when MnO2 is the substance who oxidized here so, the oxidizing agent and the anode here is Li.
and when the molar mass of Li is = 7 g/mol
and in our reaction equation we have 1 mole of Li will give 3.15 V of the electrical energy
that means that :
7 g of Li gives → 3.15 V
So 1 g of Li will give→ ???
∴ The E per gram = 3.15 V / 7 g of Li
= 0.45 V
Answer:
The answer is in the explanation
Explanation:
Single displacement reactions: In these reactions, a more reactive element kicks out a less reactive element from a compound.
Ex. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
In this example, Zn is more reactive than H, then Zn displaces H from the compound.
Double displacement reactions: In these kind of reactions 2 elements are displaced from the different compounds, these elements interchange positions.
Ex. CuCl2(aq) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 AgCl(s)
In the example, Cu displaces Ag and Ag displaces Cu, they interchange positions.
