3 years ago

Can someone pleaseeeeeeeeeee check my work to see if I did it right?

Chemistry

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

Its right!

Explanation:

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A solution contains 22.4 g glucose (C6H12O6 ) dissolved in 0.500 L of water. What is the molality of the solution

Shalnov [3]

Answer:

Molality is 0.25 m

Explanation:

Molality → Moles of solute / kg of solvent

We need the moles of solute → 0.124 moles

22.4 g . 1 mol / 180 g = 0.124 moles

We need the mass of solvent in kg. We determine the mass of solvent with density.

Density = Mass / Volume

Mass = Density . volume → 1 g/mL . 500 mL = 500 g

If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg

In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m

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Answer:

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Explain what the terms "Pyranose" and "Furanose" represent

Illusion [34]

Answer:

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Explanation:

Pyranose is collective term for the saccharides which have chemical structure which includes six-membered ring that consists of one oxygen atom and five carbon atoms.

Furanose is collective term for carbohydrates which have chemical structure which includes five-membered ring system that consists of one oxygen atom and four carbon atoms.

Glucose exists both in pyranose and furanose form. It's structure is shown in image.

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