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sp2606 [1]
3 years ago
10

Which of the following is TRUE about ideal gas particles?

Chemistry
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

The answer is A.

Explanation:

Gas particles do not have a fixed position or volume so they move in <em>r</em><em>a</em><em>n</em><em>d</em><em>o</em><em>m</em><em> </em><em>s</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>d</em><em>i</em><em>r</em><em>e</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em>s</em>.

(Correct me if I am wrong)

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alina1380 [7]
D Direction of motion I hope this helps
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True or false elements in the same colum have simular properties
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True since ithave same number of electrons and protons
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Need help asap!
Scilla [17]

Answer: 1.  C. polar covalent: electrons shared between silicon and sulfur but attracted more to the sulfur

2. B)  NH_3

3. B) Fluorine

Explanation:

1. A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

Electronegativity difference = electronegativity of sulphur- electronegativity of silicon = 2.5 -1.8 = 0.7

Thus as electronegativity difference is less than 1.7 , the cond is polar covalent and as electronegativity of sulphur is more , the electrons will be more towards sulphur.

2. A molecular compound is usually composed of two or more nonmetal elements. Example: NH_3

Ionic compound is formed by the transfer of electrons from metals to non metals. Example: Mg_3N_2 , AlCl_3 and LiBr

3.  For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here K is having an oxidation state of +1 and as the compound formed is KZ, the oxidation state of non metallic element Z should be -1. Thus the element Z is flourine which exists as diatomic gas F_2

4 0
3 years ago
Does the volume of a liquid change
nydimaria [60]

Answer:

Yes it does change

Explanation:

6 0
3 years ago
The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof
sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O     ⇄   H₃O⁺ +   F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the  [ H₃O⁺ ]  ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1  relation , we will also have [F⁻ ]. The  [ HF ] is given in the question so we have all the information that is needed to  compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻²  M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x  ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴  

(Rounded to two significant figures, the powers of 10 have infinite precision )

4 0
3 years ago
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