If we test the solubility of Salt, Sugar, and Epsom Salt then what will dissolve the most

A baseball player hits a ball. Which is the best description of the energy of the ball as it flies over the pitcher’s head?

Elan Coil [88]

The right option is; b. mechanical

Mechanical energy is the best description of the energy of the ball as it flies over the pitcher’s head.

Mechanical energy is the energy that an object acquires due to its position or due to its motion. From the question, the baseball player has chemical potential energy (stored as food) which is transformed into work. As the baseball player hits the ball, there is energy exchange in which the ball acquires energy to perform its work. The energy obtained by the ball upon which work is done is called mechanical energy.

3 0

3 years ago

Read 2 more answers

This for number 8 and 9

3241004551 [841]

Okay for 8 it is the maximum levels will be higher and for 9 is poor circulation leads to lack of nutrients and oxygen

6 0

3 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago

Laser fusion Group of answer choices uses chemical reactions to produce energy uses nuclear reactions to produce energy implodes

KonstantinChe [14]

Answer:

Uses nuclear reactions to produce energy

Implodes a fuel pellet

Explanation:

Laser fusion is a method of initiating nuclear fusion reactions through heating, and compressing fuel pellets containing deuterium and tritium using high energy density laser beams. Lase fusion is also known as inertial confinement fusion and the energy produced by the process is known as Laser Inertial Fusion Energy, LIFE.

During the process of laser fusion, small pellets of deuterium-tritium (DT) isotopes mixture are fed into a blast chamber where they are compressed to high densities using a number of amplified laser beams in the chamber.

The high energy density of the beams as well as the heat produced due to compression, induces the thermonuclear explosion ignition resulting in the production of high energetic products such as charged particles, x-rays and neutrons. The energy produced is absorbed and stored as heat in a blanket that is then used in a steam thermal cycle to generate electrical power.

There are two methods of compression of the DT pellet: direct and indirect-drive laser fusions.

However, there are a number of limitations to energy production by this process. One limitation is that the process is extremely inefficient in energy energy production. Also, the heat produced by the flashtubes results innthe deformation of the laser glass.

3 0

3 years ago

What is the maximum concentration of Ag⁺ that can be added to a 0.00750 M solution of Na₂CO₃ before a precipitate will form? (Ks

Firlakuza [10]

Answer:

$\large \boxed{1.64\times 10^{-5}\text{ mol/L }}$

Explanation:

Ag₂CO₃(s) ⇌2Ag⁺(aq) + CO₃²⁻(aq); Ksp = 8.10 × 10⁻¹²

2x 0.007 50 + x

$K_{sp} =\text{[Ag$^{+}$]$^{2}$[CO$_{3}^{2-}$]} = (2x)^{2}\times 0.00750 = 8.10 \times 10^{-12}\\0.0300x^{2} = 8.10 \times 10^{-12}\\x^{2} = 2.70 \times 10^{-10}\\x = \sqrt{2.70 \times 10^{-10}} = \mathbf{1.64\times 10^{5}} \textbf{ mol/L}\\\text{The maximum concentration of Ag$^{+}$ is $\large \boxed{\mathbf{1.64\times 10^{-5}}\textbf{ mol/L }}$}$

3 0

3 years ago