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Maksim231197 [3]
3 years ago
15

Which of the following is not a condition that must be met before you can use the quadratic formula to find the solutions of an

equation?
A. The coefficient of the x2-term can't be zero.
B. There can be no term whose degree is higher than 2.
C. One side of the equation must be zero.
D. The coefficient of the x2-term must be positive.
Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

"The coefficient of x²-term must be positive"

D is correct

Step-by-step explanation:

Given: y=ax^2+bx+c

We are given a quadratic equation. The quadratic equation whose degree is 2.

The leading coefficient of quadratic can't be 0.

y=ax^2+bx+c

a\neq 0

The highest degree should be 2

For quadratic formula:

ax^2+bx+c=0

First we make right side 0 and then apply quadratic formula.

Hence, The condition which is not true for quadratic formula "The coefficient of x²-term must be positive"

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Which triangle would be most helpful in finding the distance between the points (-4, 3) and (1,-2) on the coordinate
earnstyle [38]

Answer:

On a coordinate plane, a triangle has points (negative 4, 3), (negative 4, negative 2), (1, negative 2).

Step-by-step explanation:

The points (-4,3), (1,2) and (-4, -2) would form a right triangle when graphed and connected by lines.

(-4,3), (1,2) and (1,3) would also work as well

5 0
2 years ago
Please choose answer choice a,b,c or d
dmitriy555 [2]

Answer:

A. -4

Step-by-step explanation:

Slope is rise over run, or y2-y1 / x2-x1.

\frac{y2-y1}{x2-x1} = \frac{-4-8}{2--1} =\frac{-12}{3} = -4

<u>The slope is A. -4.</u>

Let's see--does that make sense? A slope of four would be pretty steep, and that matches the graph. It also should be negative because the line goes down and to the right, not up and to the right, so -4 makes sense!

4 0
3 years ago
Describe the patterns below in words:<br><br> a) 1, 4, 9, 16, 25...<br> b) 1, 2, 4, 7, 11...
Makovka662 [10]
A)Add 3 and the continue to add 2 more to three each time to get the next number
B)add 1 and add one to the number one each time to get the the next number
7 0
3 years ago
Read 2 more answers
Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
3 years ago
I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!
IRINA_888 [86]

Answer:

<em>Answer is option</em><em> </em><em>b</em><em>)</em><em> </em>

<em>{(x - 3)}^{2}  +  {(y - 4)}^{2}  = 400</em>

<em>Your</em><em> </em><em>guess</em><em> </em><em>was</em><em> </em><em>right</em><em>.</em>

Step-by-step explanation:

the \: question \: states \: that \:  \\ distance \: between \: two \: points \: is \: 20 \: units \:  \\ and \: the \: two \: points \: are \: (x,y) \:  \: and \:  \: (3 ,- 4) \\ distance \: formula \\  =   \sqrt{ {(x1 - x2) }^{2} +  {(y1 - y2)}^{2}  }  \\ on \: substituting \: the \: values \: in \: formula \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y - ( - 4))}^{2}  }  \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y + 4)}^{2}  }  \\ now \: squaring \: on \: both \: sides \\ 400 =  {(x - 3)}^{2}  +  {(y + 4)}^{2}  \\ hence \: the \: answer \: is \: option \: b)

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
3 years ago
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