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4 years ago

Where is the blue dot on the number line

Mathematics

2 answers:

Artyom0805 [142]4 years ago

7 0

Answer:

-11.3

Step-by-step explanation:

Take -10.5 - (-11) = -10.5 +11 = .5

There are 5 spaces between -10.5 and -11, so take

.5 / 5 spaces = .1

Each space is .1

We are going down , so subtract .1 each time we go down

Starting at -11, we go down 3

-11 - .3 = -11.3

Whitepunk [10]4 years ago

6 0

The blue dot is at -11.3 on the number line.

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A large tank is partially filled with 100 gallons of fluid in which 20 pounds of salt is dissolved. Brine containing 1 2 pound o

sertanlavr [38]

Answer:

Step-by-step explanation:

From the given information:

$R_{in} = ( \dfrac{1}{2} \ lb/gal) (6)\ gal /min \\ \\R_{in} = 3 \ lb/min$

Given that the solution is pumped at a slower rate of 4gal/min

Then:

$R_{out} = \dfrac{4A}{100+(6-4)t}$

$R_{out}= \dfrac{2A}{50+t}$

The differential equation can be expressed as:

$\dfrac{dA}{dt}+ \dfrac{2}{50+t}A = 3 \ \ \ ... (1)$

Integrating the linear differential equation; we have::

$\int_c \dfrac{2}{50 +t}dt = e^{2In |50+t|$

$\int_c \dfrac{2}{50 +t}dt = (50+t)^2$

multiplying above integrating factor fields; we have:

$(50 +t)^2 \dfrac{dA}{dt} + 2 (50 + t)A = 3 (50 +t)^2$

$\dfrac{d}{dt}\bigg [ (50 +t)^2 A \bigg ] = 3 (50 +t)^2$

$(50 + t)^2 A = (50 + t)^3+c$

A = (50 + t) + c(50 + t)²

Using the given conditions:

A(0) = 20

⇒ 20 = 50 + c (50)⁻²

-30 = c(50) ⁻²

c = -30 × 2500

c = -75000

A = (50+t) - 75000(50 + t)⁻²

The no. of pounds of salt in the tank after 35 minutes is:

A(35) = (50 + 35) - 75000(50 + 35)⁻²

A(35) = 85 - $\dfrac{75000}{7225}$

A(35) =69.6193 pounds

A(35) $\simeq$ 70 pounds

Thus; the number of pounds of salt in the tank after 35 minutes is 70 pounds.

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3 years ago

Human body temperatures have a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit. Convert 103

Artist 52 [7]

Answer:

<em>z-score will be: 7.741.... and it will be unusual. </em>

Step-by-step explanation:

Human body temperatures have a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit.

So here, $\mu= 98.20$ and $\sigma= 0.62$

<u>Formula for z-score</u> is: $z= \frac{X-\mu}{\sigma}$

Thus, the z-score for 103.00 degrees Fahrenheit will be.......

$z(X=103.00)= \frac{103.00-98.20}{0.62}=7.741...$

As, here the z-score is more than 2 standard deviations above the mean, so 103.00 degrees Fahrenheit is unusual for human body temperature.

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3 years ago

you stop for lunch at a local pizza ahop where each pizza is cut into 8 sices. would your hunger be better satisifued with one s

Lady_Fox [76]

Answer:

Hello there! How are you doing? I am doing fine! I'll answer the question now.

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Hope this helped! Your welcome! I can help with other history stuff too! And byee! :)

Step-by-step explanation:

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3 years ago

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ohaa [14]

Answer:

y=0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2.6y-4/15y+7/6y=7/3y

2.6y-(-)4/15y+7/6y=7/3y

(2.6y-4/15y+7/6y)=7/3y (combine like terms)

7/2y = 7/3y

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7/2y - 7/3y = 7/3y - 7/3y

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6/7 . 7/6y = 6/7 . 0

y = 0

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