It is given that the area of the circular garden = 100
Area of circle with radius 'r' =
We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.
Since, area of circular garden = 100
So, r = 5.6 ft
r = 6 ft (approximately)
Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.
So, Option A is the correct answer.
Answer: .75
Brainliest plzzzzzzzzzzz
Step-by-step explanation:
Example of distributive property: 4(2+3)
The first step is to multiply the 4 and the 2
It will now look like 8+4(3)
Now you must multiply the 4 and the 3
Then it will look like 8+12
In which 8+12=20
Answer:
y ≤ -4x+25
Step-by-step explanation:
First we need to figure out the equation for the line
The y intercept is 25
Next figure out the slope
slope = (y2-y1)/((x2-x1)
= (49-25)/(-6-0)
= 24/-6
= -4
The equation for a line in slope intercept form is y = mx+b
y = -4x+25
This is a solid line so our inequality will have an equals in it.
It is shaded below, so y is less than.
If it was shaded above, y would be greater than
y ≤ -4x+25
Answer:
a). We want to know how much each point was worth.
b).
c). Each problem worth 3 points.
Step-by-step explanation:
a). We want to know how much each problem was worth. Because we have the total points of the test, and how much was the bonus. But we still don't know the worth of each problem.
b). We know that the total points of the test were 41, and the bonus 5 points. There were 12 problems on the test and we are going to use "x" for the unknown part (how many points each problem was worth).
The equation is :
Why 12x? Because if you multiply the twelve problems of the test with the worth of each one and then add the 5 points of the bonus you will obtain the total points of the test (41).
c). Now we have to solve the equation, this means that we have to clear "x":
Subtract 5 from both sides.
Finally divide in 12 both sides of the equation:
Then each problem worth 3 points.