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Maslowich
2 years ago
7

Me podrian ayudar en esto porfavor

Mathematics
1 answer:
Vilka [71]2 years ago
4 0

Answer:

desafortunadamente no hablo español jajaja aunque lo estoy hablando bien no voy a ayudar solo quiero puntos gratis

Step-by-step explanation:

You might be interested in
A test worth 125 points has 49 questions on it. Multiple Choice questions are worth 2 points each and short answer questions are
Charra [1.4K]

Answer:

There were 40 2-point questions and 9 3-point questions.

Step-by-step explanation:

To solve this situation, write two equations. One for the number of questions and one for the number of points.

Let x be the number of 2 point questions.

Let y be the number of 5 point questions.

x + y = 49

Now since x are each worth 2 points, the total points is 2x.

And since y are each worth 5 points, the total points is 5y.

So 2x + 5y = 125. Substitute one of the equations into the other to solve for the variables.

x + y = 49 becomes x = 49 - y. Substitute it.

2(49-y) + 5y = 125

98 - 2y + 5y = 125

98 + 3y = 125

3y = 27

y = 9

Substitute y = 9 back into the equation x = 49 - y to find x.

x = 49 - 9

x = 40

5 0
3 years ago
Find the surface area of the cube (5.1cm tall)
joja [24]

Answer:

156.06cm

Step-by-step explanation:

sa=LW6

6 0
3 years ago
Read 2 more answers
4/11 divided by 1/7 <br>​
MA_775_DIABLO [31]
4/11•7/1=28/11
Answer: 28/11 or 2 6/11
5 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST HELP ASAP ASAP
Alina [70]

Answer:

B

Step-by-step explanation:

I got this answer correct on a test

5 0
2 years ago
A certain disease has an incidence rate of 0.1%. If the false negative rate is 8%
defon

Answer: 0.31 or 31%

Let A be the event that the disease is present in a particular person

Let B be the event that a person tests positive for the disease

The problem asks to find P(A|B), where

P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))

In other words, the problem asks for the probability that a positive test result will be a true positive.  

P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)

P(A) = 0.009 (probability the disease is present in any particular person)

P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)

P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)

P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)

= 0.00882 / 0.02864 = 0.30796

*round however you need to but i am leaving it at 0.31 or 31%*

If you found this helpful please mark brainliest

3 0
2 years ago
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