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3 years ago

Can someone help me on this I’m stuck pleaseee anyone

Mathematics

1 answer:

Svetlanka [38]3 years ago

7 0

Answer:

1a. 0 pounds of grapes costs 0 dollars.

1b. 1 pound of grapes costs 3 dollars.

2a. There are 0 batteries in 0 packs of batteries.

2b. There are 10 batteries in 1 pack of batteries.

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katie has 60 flowers. she wants to divide into two groups so the ratio is 2:3 how many flowers in each group

olasank [31]

ratio 2:3 2+3 =5

60 /5 = 12

2*12 = 24

3* 12 = 36

24 to 36

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3 years ago

What is the distance between (3,2) and (3,-8)

prohojiy [21]

The answer is (0,-10)

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3 years ago

If 3x + 2 = 4, what is the value of 6x - 4?<br> 2<br> 8<br> 0<br> -2

Sladkaya [172]

Answer:

Step-by-step explanation:

3x + 2 = 4

4-2 = 3x

2 = 3x

x = 2/3

2/3 x 6 = 12/3 = 4 - 4 = 0

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3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago

Ms. O'Conner took a poll of 80 students to find out how they get to school. How many more students get to school on a bus than i

il63 [147K]

Answer:

I need the dull question

Step-by-step explanation:

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3 years ago