4 years ago

Find a pattern for the sum of 4 times a number and twice the sum of the same number and 3

1 answer:

6 0

4n+2(n+3) or 6n+6
when n=1 then the result is 12
when n=2 then the result is 18
when n=3 then the result is 24

goes up by 6, starts at 12

12,18,24,30,36,42...

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Step-by-step explanation:

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