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bogdanovich [222]
3 years ago
14

Suppose we want to choose 5 objects,without replacement from 16 distinct objects

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

4368 ways

Step-by-step explanation:

We want to choose 5 objects,without replacement from 16 distinct objects.

We can use combination in this case. The formula for the combination is given by :

_{n}C_r=\dfrac{n!}{r!(n-r)!}

We have, n = 16 and r = 5

So,

_{16}C_5=\dfrac{16!}{5!(16-5)!}\\\\_{16}C_5=\dfrac{16!}{5!11!}\\\\=4368

So, there are 4368 ways in which we want to choose  5 objects,without replacement from 16 distinct objects.

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