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bogdanovich [222]
3 years ago
14

Suppose we want to choose 5 objects,without replacement from 16 distinct objects

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

4368 ways

Step-by-step explanation:

We want to choose 5 objects,without replacement from 16 distinct objects.

We can use combination in this case. The formula for the combination is given by :

_{n}C_r=\dfrac{n!}{r!(n-r)!}

We have, n = 16 and r = 5

So,

_{16}C_5=\dfrac{16!}{5!(16-5)!}\\\\_{16}C_5=\dfrac{16!}{5!11!}\\\\=4368

So, there are 4368 ways in which we want to choose  5 objects,without replacement from 16 distinct objects.

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95 degrees
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Hi how are you doing?. Is that nice enough

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4 years ago
4.) Complete the equations of the system in slope-intercept form. Use a decimal for the slope if necessary.
marissa [1.9K]
The slope is found by y_{2} -y_{1} / x_{2}  - x_{1}
Line 1: y2 is 6, y1 is 4, x2 is 2, x1 is -2
6-4/2- -2= 2/4=1/2

Slope intercept is written as y= mx+b. m is the slope, and b is the intercept (the intercept is the value of y when x is 0). To find out the intercept, we plug in values of y, m and x
4= 1/2(-2) +b
4=-1+b
5=b
The equation for line 1 is y= 1/2x +5
Using the same formulas as above, the equation for line 2 is y= 3x+4
The solution to the system is a point where both lines would meet in the graph, or a set of x and y values that satisfies both equations. 
y= 3x+4
y= 1/2x+5
3x+4 = 1/2x+5
3x= 1/2x +5 -4
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4 0
4 years ago
We saw two distributions for triathlon times: N(µ = 4313, Ï = 583) for Men, Aged 30 - 34 and N(µ = 5261, Ï = 807) for the Wome
zzz [600]

Answer:

a) 3354 seconds

b) 6294 seconds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) The cutoff time for the fastest 5% of athletes in the men's group, i.e. those who took the shortest 5% of time to finish.

\mu = 4313, \sigma = 583

The cutoff for the shortest 5% is the 5th percentile, which is X when Z has a pvalue of 0.05. So X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 4313}{583}

X - 4313 = -1.645*583

X = 3354

Cutoff of 3354 seconds.

(b) The cutoff time for the slowest 10% of athletes in the women's group.

\mu = 5261, \sigma = 807

The slowest 10% is the 10% that takes more time, so the cutoff is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 5261}{807}

X - 5261 = 1.28*807

X = 6294

Cutoff time of 6294 seconds

5 0
4 years ago
Easy question practically free points
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The answer is 6x+12. Have a GREAT day!!!! :)

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