I think the correct answer would be both the mean and median are appropriate measures of center. Since the given data set is ordinal and is not skewed that much. Also the values of such would be close with each other. Hope this answers the question.
Answer:
The answer is 4 + √15 .
Step-by-step explanation:
You have to get rid of surds in the denorminator by multiplying it with the opposite sign :
![\frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B5%7D%20%20%2B%20%20%5Csqrt%7B3%7D%20%7D%7B%20%5Csqrt%7B5%7D%20%20-%20%20%5Csqrt%7B3%7D%20%7D%20)
![= \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B5%7D%20%2B%20%20%5Csqrt%7B3%7D%20%20%7D%7B%20%5Csqrt%7B5%7D%20%20-%20%20%5Csqrt%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%7B5%7D%20%20%2B%20%20%5Csqrt%7B3%7D%20%7D%7B%20%5Csqrt%7B5%7D%20%20%2B%20%20%5Csqrt%7B3%7D%20%7D%20)
![= \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%7B%28%20%5Csqrt%7B5%7D%20%2B%20%20%5Csqrt%7B3%7D%20%29%20%7D%5E%7B2%7D%20%7D%7B%28%20%5Csqrt%7B5%7D%20-%20%20%5Csqrt%7B3%7D%20%29%28%20%5Csqrt%7B5%7D%20%20%2B%20%20%5Csqrt%7B3%7D%29%20%20%7D%20)
![= \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Cfrac%7B%20%7B%28%20%5Csqrt%7B5%7D%20%29%7D%5E%7B2%7D%20%20%2B%202%28%20%5Csqrt%7B5%7D%20%29%28%20%5Csqrt%7B3%7D%29%20%2B%20%20%7B%28%20%5Csqrt%7B3%7D%29%20%7D%5E%7B2%7D%20%20%7D%7B%20%7B%28%20%5Csqrt%7B5%7D%29%20%7D%5E%7B2%7D%20-%20%20%7B%20%28%5Csqrt%7B3%7D%20%29%7D%5E%7B2%7D%20%20%7D%20)
![= \frac{5 + 2 \sqrt{15} + 3 }{5 - 3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B5%20%2B%202%20%5Csqrt%7B15%7D%20%2B%203%20%7D%7B5%20-%203%7D%20)
![= \frac{8 + 2 \sqrt{15} }{2}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B8%20%2B%202%20%5Csqrt%7B15%7D%20%7D%7B2%7D%20)
![= 4 + \sqrt{15}](https://tex.z-dn.net/?f=%20%3D%204%20%2B%20%20%5Csqrt%7B15%7D%20)
Answer:
4 and 6
Step-by-step explanation:
Judging by the table and how x = 1 and y = 2, you can estimate that y is twice as much as x.
This is supported by the equation, if you take 2 and multiply it by x (1) and take 3 and multiply it by y (2), then add the 2x1 (2) and 3x2 (6), you should get 8.