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3 years ago

The vertex of this parabola is at (4, -3). When the x-value is 5, the

1 answer:

7 0

$The\ vertex\ form:y=a(x-k)^2+h\\\\where\ (k;\ h)\ \ are\ coordinates\ of\ vertex\\------------------------\\y=a(x-4)^2-3\\\\the\ point\ on\ parabola\ (5;-6)\\Put\ x=5\ and\ y=-6\ to\ equation:\\\\a(5-4)^2-3=-6\\a(1)^2=-6+3\\a=-3\\\\Answer:y=-3(x-4)^2-3=-3(x^2-8x+16)-3\\\\=-3x^2+24x-48-3=-3x^2+24x-51$

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Find the value of x from the figure given below:

NemiM [27]

Answer:

$sinB = \frac{x}{34}=\frac{5}{17} => \frac{x}{34}=\frac{5}{17}\\\\ x= \frac{5}{17}.34 =10$

Step-by-step explanation:

6 0

2 years ago

At a certain time of the day, a tree that is x meters tall casts a shadow that is x-49 meters long. If the distance from the top

nikklg [1K]

The height of the tree is 60 meters.

Explanation:

Let the height of the tree be x. The tree casts a shadow of $x-49$ meters and the distance from the top of the tree to the end of the shadow is $x+1$ meters.

The sides of the triangle are attached in the image below:

Using pythagoras theorem,

$x^{2}+(x-49)^{2}=(x+1)^{2}$

Expanding, we get,

$2 x^{2}-98 x+2401=x^{2}+2 x+1$

$2 x^{2}-98 x+2400=x^{2}+2 x$

$2 x^{2}-100 x+2400=x^{2}$

$x^{2}-100 x+2400=0$

Solving the equation using the quadratic formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , we get,

$x=\frac{-(-100)\pm\sqrt{(-100)^{2}-4 \cdot 1 \cdot 2400}}{2 \cdot 1}$

Simplifying, we have,

$x=\frac{100\pm\sqrt{10000-9600}}{2}$

$x=\frac{100\pm\sqrt{400}}{2}$

$x=\frac{100\pm{20}}{2}$

Thus,

$x=\frac{100+20}{2} \\x=\frac{120}{2} \\x=60$ and $x=\frac{100-20}{2} \\x=\frac{80}{2} \\x=40$

where the value $x=40$ is not possible because substituting the value $x=40$ in $x-49$ results in negative solution. Which is not possible.

Hence, the value of x is 60.

Thus, The height of the tree is 60 meters.

7 0

2 years ago

Find the measure of each missing angle in the parallel lines and transversals below

never [62]

The equation is 10x=2x+60

x=15/2

∠CFH=75

∠CBD= 75

We are dealing with parallel lines, which are the lines that are equidistant to each other and never meet, will never meet, when such lines are crossed by another line called the transversal creates many angles such as corresponding angles, vertical angles, alternate interior angles, alternate exterior angles, consecutive angles.

Since, angle CBD and angle CFH are the corresponding angles and they are equal to each other, we are given CBD=2x+60 and CFH = 10x

therefore , 10x=2x+60

=>10x-2x=60

=>8x=60

x=15/2

So, the angle CBD= 2x+60= 2(15/2)+60= 75

and the angle CFH = 10x= 10(15/2)= 75

To know more about parallel lines refer to the link brainly.com/question/16701300?referrer=searchResults.

#SPJ1

6 0

8 months ago

Factor the expression45c+10d

Norma-Jean [14]

45c = 5 · 9c
10d = 5 · 2d

45c + 10d = 5 · 9c + 5 · 2d = 5(9c + 2d)

6 0

3 years ago

X^2+ 17x+91=0<br> Help please!!

Morgarella [4.7K]

Answer:

x^2+17x+91=0

a = 1; b = 17; c = +91;

Δ = b2-4ac

Δ = 172-4·1·91

Δ = -75

Delta is less than zero, so there is no solution for the equation

Step-by-step explanation:

6 0

2 years ago