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3 years ago

Terbium-160 has a half-life of about 72 days.

1 answer:

5 0

For the half-life of a certain substance, the equation that would best represent the scenario is,
At = Ao(0.5^t/n)
where At is the amount at any time t, Ao is the original amount, and n is half-life. Substituting the known values,
At = (220 mg)(0.5^(396/72)
At = 4.86 mg
Thus, after 396 days, there will only be 4.86 mg of Terbium-160.

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Write 9 decimals with one decimal place that when rounded to the nearest one round to 7

FinnZ [79.3K]

7.030124314 they all just have to be less then 5

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3 years ago

Read 2 more answers

What is the greatest common factor c^2d^2

Brums [2.3K]

Answer:

Step-by-step explanation:

Since there are no common prime factors, the only common factor for c²d² is 1, therfore it stays as is, c²d².

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3 years ago

Horizontal pieces can be produced at a rate of 200 per labor hour. a carpenter uses 500 horizontal pieces and 22 vertical pieces

ira [324]

The number of vertical pieces will be 28. Then the correct option is A.
The number of horizontal pieces will be 600. Then the correct option is B.

<h3>What is decision-making?</h3>

The process of making choice is by identifying the correct decision, gathering information, and assessing alternative solutions.

Horizontal pieces can be produced at a rate of 200 per labor hour.

A carpenter uses 500 horizontal pieces and 22 vertical pieces while making racks for an hour.

You have 900 horizontal pieces and 50 vertical pieces in stock right now.

For the next hour, you assign Juan to rack making, Debbie to trim making, and both mike and stan to horizontal piece production.

1. Then at the end of the next hour, the number of vertical pieces available in stock will be

→ 50 - 22

→ 28

Thus, the number of verticle pieces will be 28.

2. Then at the end of the next hour, then the number of horizontal pieces available in stock will be

→ 900 + 200 - 500

→ 600

More about the decision-making link is given below.

brainly.com/question/3369578

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7 0

2 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

<u /> $\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

<u /> $\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

2 years ago

The angle of elevation to the top of a very tall building is found to be 13° from the ground at a distance of 1 mi from the base

Marta_Voda [28]

Tan(Θ)=(h/distance from base)
Θ=13 degrees, 1mile=5280 ft
tan(13)=(h/5280 ft)
5280tan(13)=h
h=1218.984049
h=1219 ft

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3 years ago