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Naddik [55]
2 years ago
7

9. Date Units Purchased Cost Per Unit

Mathematics
1 answer:
Nastasia [14]2 years ago
3 0

Answer:

$219.00.

Step-by-step explanation:

January 1, 10 units @ $8 (10 x 8)          = $80

January 18, 50 units @ $9 (50 x 9)      = $450

February 20, 20 units @ $11 (20 x 11)  = $220

March 15, 10 units @ $12 (10 x 12)        = 120

Ending Inventory = 19 unit

Ending Inventory = (10 x12) + (9 x 11) = $219

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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

For this case we have the following info given:

ME=0.03 the margin of error desired

Conf= 0.95 the level of confidence given

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

the critical value for 95% of confidence is z=1.96

We can use as estimator for the population of interest \hat p=0.5. And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

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Congrats on making it to integrals!
Basically you need to integral your function because integral rate in respect to time = total amount.
Also your bounts are (2001-1990,2006-1990)=(11,16)

Thus we take integral like:
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