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Naddik [55]
3 years ago
7

9. Date Units Purchased Cost Per Unit

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

$219.00.

Step-by-step explanation:

January 1, 10 units @ $8 (10 x 8)          = $80

January 18, 50 units @ $9 (50 x 9)      = $450

February 20, 20 units @ $11 (20 x 11)  = $220

March 15, 10 units @ $12 (10 x 12)        = 120

Ending Inventory = 19 unit

Ending Inventory = (10 x12) + (9 x 11) = $219

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the number to the right of the 7

Step-by-step explanation:

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The input is 8 and the output is 26 what's the rule?
LuckyWell [14K]

Answer:

It could either be x * 3.25 or x + 18

Step-by-step explanation:

8 * 3.25 = 26

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Ok so I’m thinking that s = 93 because first I multiply first sides of the equation by -4, which was s-61=32. Then I moved the constant to the right hand side and change its sign which will be s=32+61. After I did all of that I added the numbers together and got 93..... therefore s=93
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2 years ago
A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen
Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}

The restriction is that the perimeter have to be 12 ft at most:

P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12

We can express b in function of a as:

2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a

Then, the area become:

A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2

To maximize the area, we derive and equal to zero:

\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36

Then, b is:

b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68

3 0
3 years ago
I need help it’s not c I tried but it’s not that plz someone help me with this I need help not sure what to do
Kobotan [32]

Answer:

a is the answer because it is

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3 years ago
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