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3 years ago

9. Date Units Purchased Cost Per Unit

Mathematics

1 answer:

Nastasia [14]3 years ago

3 0

Answer:

$219.00.

Step-by-step explanation:

January 1, 10 units @ $8 (10 x 8) = $80

January 18, 50 units @ $9 (50 x 9) = $450

February 20, 20 units @ $11 (20 x 11) = $220

March 15, 10 units @ $12 (10 x 12) = 120

Ending Inventory = 19 unit

Ending Inventory = (10 x12) + (9 x 11) = $219

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1. The science club constructed a pyramid with a square base out of paper clips. The height of the pyramid is 2.5 feet. One side

elena-14-01-66 [18.8K]

Answer:

Part 1) The slant height of the pyramid is $2.80\ ft$

Part 2) The length of the third side of the window is $20.78\ in$

Part 3) The building's slant height is $53.85\ ft$

Step-by-step explanation:

Part 1) we know that

To find out the slant height of the pyramid, apply the Pythagorean Theorem

Let

l ----> the slant height of the pyramid

h ---> the height of the pyramid

b ---> the length side of the square base

$l^2=h^2+(b/2)^2$

we have

$h=2.5\ ft\\b=2.5\ ft$

substitute the given values

$l^2=2.5^2+(2.5/2)^2$

$l^2=2.5^2+(1.25)^2$

$l^2=7.8125$

$l=2.80\ ft$

Part 2) Let

c ----> the hypotenuse of a right triangle (the greater side)

a ---> the measure of one leg of the right triangle

b ---> the measure of the other leg of the right triangle

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

we have

$c=24\ in\\a=12\ in$

substitute the given values and solve for b

$24^2=12^2+b^2$

$b^2=24^2-12^2$

$b^2=432$

$b=20.78\ in$

Part 3) Let

l ----> the building's slant height

h ---> the height of the building

r ---> the radius of the base of the building

Applying the Pythagorean Theorem

$l^2=h^2+r^2$

we have

$h=50\ ft\\r=20\ ft$

substitute the given values

$l^2=50^2+20^2$

$l^2=2,900$

$l=53.85\ ft$

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Nataly_w [17]

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162 water bottles in 9 cases =

Komok [63]

I believe u would divide, 162 divided by 9= 18

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