Question

A 1.35 ×103 kg car rounds a circular turn of radius 11.9 m. The acceleration of gravity is 9.81 m/s 2 . If the road is flat and the coefficient of static friction between the tires and the road is 0.67, how fast can the car go without skidding? Answer in units of m/s.

Answer 1

Answer:

velocity = 8.84 m/s

Explanation:

given data

radius r =  11.9 m

acceleration of gravity g = 9.81 m/s²

static friction μ = 0.67

to find out

how fast can the car go without skidding

solution

we get here velocity that is car go without skidding is express as

force = $\frac{mv^2}{r}$

force = μ × mg

μ × mg = $\frac{mv^2}{r}$

v² = μ × r × g

v = $\sqrt{\mu *r*g}$    ..................1

v = $\sqrt{0.67 *11.9*9.81}$

v = 8.84 m/s

velocity = 8.84 m/s