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3 years ago

A force acting on a moving ball causes its motion to change. This force stays constant.

Physics

1 answer:

sashaice [31]3 years ago

8 0

Answer:

you stop the ball or bring it to a different direction

Explanation:

i don't know if this helps. i didn't take physics yet. but i hope this helps.

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"Two identical positive charges exert a repulsive force of 6.7 × 10−9 N when separated by a distance 3.5 × 10−10 m. Calculate th

Tamiku [17]

Answer:

The charge of each charge is $3.02\times10^{-19} C$

Explanation:

When yo have two charged particles they interact exerting an electrostatic force in the other particles, the magnitude of the electrostatic force between two particles is:

$F_{e}=k\frac{\mid q_{1}q_{2}\mid}{r^{2}}$ (1)

with q1 and q2 the charges, r the distance between them and k the Coulomb's constant ( $k=9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}}$ )

Because the charges we're dealing are identical positive q1=q2, then (1) is:

$F_{e}=k\frac{\mid q^2 \mid}{r^{2}}$

Using the values the problem give us:

$6.7\times10^{-9}=8.98755\times10^{9}\frac{\mid q^2 \mid}{(3.5\times10^{-10})^{2}}$

solving for q:

$q=\sqrt{\frac{(3.5\times10^{-10})^{2}6.7\times10^{-9}}{8.98755\times10^{9}}}$

$q= 3.02\times10^{-19} C$

8 0

3 years ago

Answer if you know the answer only.

borishaifa [10]

Answer:

4A*12Ω=48V

Explanation:

7 0

3 years ago

A baseball player throws a ball horizontally at the same moment another baseball player jobs a second ball straight down from th

attashe74 [19]

I don't know what you mean when you say he "jobs" the other ball, and the answer to this question really depends on that word.

I'm going to say that the second player is holding the second ball, and he just opens his fingers and lets the ball drop, at the same time and from the same height as the first ball.

Now I'll go ahead and answer the question that I've just invented:

Strange as it may seem, both balls hit the ground at the same time ... the one that's thrown AND the one that's dropped. The horizontal speed of the thrown ball has no effect on its vertical acceleration, so both balls experience the same vertical behavior.

And here's another example of the exact same thing:

Say you shoot a bullet straight out of a horizontal rifle barrel, AND somebody else drops another bullet at exactly the same time, from a point right next to the end of the rifle barrel. I know this is hard to believe, but both of those bullets hit the ground at the same time too, just like the baseballs ... the bullet that's shot out of the rifle and the one that's dropped from the end of the barrel.

7 0

3 years ago

A factor that does not change in an experiment is the

quester [9]

Answer:

independent variable

Explanation:

5 0

4 years ago

Read 2 more answers

Find an expression for the kinetic energy of the car at the top of the loop.Express the kinetic energy in terms of m, g, h, and

lyudmila [28]

Answer:

K.E₂ = mg(h - 2R)

Explanation:

The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:

K.E₁ + P.E₁ = K.E₂ + P.E₂

where,

K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)

P.E₁ = Initial Potential Energy = mgh

K.E₂ = Final Kinetic Energy at the top of the loop = ?

P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)

Therefore,

0 + mgh = K.E₂ + mg(2R)

K.E₂ = mg(h - 2R)

3 0

3 years ago