Question

If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity of object 2 if the two objects collide and bounce off of each other and object 1 has a final velocity of -2 m/s?

Answer 1

The final velocity of object 2 is: 3 m/sec

What is the conservation of mass?

According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.

According to conservation of mass,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Given that,

m₁ = 50 kg

m₂ = 75 kg

u₁ = 4 m/s

u₂ = -1 m/s

v₁ = -2 m/s

v₂ = ?

Now, putting the values,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)

or, 125 = -100 + 75 v₂

or, 75 v₂ = 225

or, v₂ = 3 m/sec.

To know more about velocity refer to:

brainly.com/question/80295

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