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2 years ago

Graphing points for y=|2x-1| Pls help first person to answer get the Brainly points

Mathematics

1 answer:

Olin [163]2 years ago

8 0

Answer:

X-intercept= (1/2,0) Y-intercept= (0,1)

Step-by-step explanation:

You're welcome :)

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Factor of −21x^2+2x+8

Vanyuwa [196]

Answer:

-(7x + 4)(3x - 2)

Step-by-step explanation:

Hope this helps! have a nice day! Please consider making me Brainliest

5 0

3 years ago

To make sure the lobsters are cool but not frozen, you need to keep their temperature between 32 and 40 degrees Fahrenheit while

MaRussiya [10]

C=5/9(F-32) 5/9 =1.8 32-32= 0* 1.8 = 0 32F= 0Celsius 40-32=8* 14.4 40F= 14.4 CTemperature between 0-14 degrees Celsius

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3 years ago

What are all the solutions of x2 + 3x - 4 = 0? 3 ооооооо DONE

Allisa [31]

Answer:

x = -4, x = 1

Step-by-step explanation:

Now I do not know why you said done, but just saying, if you are done with a question, you should delete it. Now I am just going to assume you knew this and move on with the solution of the problem.

When you factor this equation, you will get (x+4)(x-1).

You can then solve for x using zero product property. The first root is -4 and the second root is 1.

4 0

2 years ago

What is an example of karma

Leokris [45]

Answer:

Negative karma: You yell at someone for being dumb, but you fail your exam.

Good karma: You give money to the homeless, and then find money on the floor.

4 0

2 years ago

Read 2 more answers

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago