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Dahasolnce [82]
3 years ago
5

A test has twenty questions worth 100 points. the test consists of

Mathematics
1 answer:
Sophie [7]3 years ago
6 0
B. False questions worth 3 ...
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The total cost of Anja’s trip to the dentist was $628.35. She paid a flat fee of $89.95 which included the checkup and cleaning
Nuetrik [128]
I may be wrong but I am sure this is the equation...
$628.35= $89.95+4x
4 0
3 years ago
SOMEONEEEE HELPPP MEEEEE PLEASEEEE!!!!
Nuetrik [128]

Answer:

{ \tt{  \tan(x) =  \frac{opposite}{adjacent}   }} \\  \\ { \tt{ \tan( \theta)  =  \frac{30}{16} }}

5 0
3 years ago
Mary Chapman had been working at First Savings for 18 years when she
DedPeter [7]

Answer:

17250

Step-by-step explanation:

6 0
3 years ago
The ratio of blue marbles to red marbles in a box is 3 to 2. if there are 12 blue marbles in a box then how many red marbles are
valkas [14]
The answer is: 8 red marbles!

This is because the equation can be written out like this
Blue to red - 3:2
Now it is, blue to red - 12:x

We have to think, what is the difference from the first equation to the second. We know the number 3 times 4 = 12, so we would do the same for the red, 2 times 4=8

If this helped, give me brainliest :)
6 0
3 years ago
Read 2 more answers
Help please, 30 points reward, i literally have no clue
Brums [2.3K]

The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.

If we apply this same process to our picture, we see that the line segment AB' crosses the line \ell at the point (1, 1)

6 0
4 years ago
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