Answer:
Step-by-step explanation:
Answer:
its the second answer i hope that helps
a) 70.1 m
The ball is moving by uniformly accelerated motion, with constant acceleration 
(acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation
where 
is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:
b) 3.9 s
We can still use the same equation we used in the previous part of the problem:
This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have
And solving for t we find
This is a right triangle, the measure of angle A is 90 degrees.
First thing to do I guess is finding B and C.
tan^-1 (7/12) = 30 degrees
tan^-1 (12/7) = 60 degrees
60 + 30 = 90
180 - 90 = 90. Therefore angle A = 90 degrees
