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Citrus2011 [14]
2 years ago
11

Write the fraction decimal and percent for the shaded area below

Mathematics
2 answers:
Nastasia [14]2 years ago
6 0

Answer:

Decimial: 0.47

Percent: 47%

Fraction: 47/100

Step-by-step explanation:

liubo4ka [24]2 years ago
4 0
Fraction: 47/100
Decimal: 0.47
Percent: 47%

Explanation: there’s 100 squares in total
and 47 are shaded
IF YOU WANT THE ANSWER OF HOW TO MAKE DECIMAL TO PERCENT OR FRACTION TO PERCENT....

JUST TYPE ON SAFARI
DECIMAL TO FRACTION
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A recreation center charges nonmembers $3 to use the pool and $5 to use the basketball courts. A person pays $42 to use the recr
Andrei [34K]
Let x = times in the pool
Let y = times in the basketball courts

42=3x+5y
x+y=12
Therefore y = 12-x
Subsitute for y
42 = 3x + 5(12-x)
42 = 3x + 60 -5x
Subtract 60
-18 = -2x
9 = x

The person used the pool 9 times.

5 0
3 years ago
PZ PLZ PLZ HELP I DO NOT UNDERSTAND THIS KINDA OF STUFF IF U DONT KNOW DO NOT ANSWER IT I ACTUALLY NEED HELP NO LINKS PLZ PLZ
ivanzaharov [21]

Answer:

176

Step-by-step explanation:

11x11=121

12x11=132

9=20-11

16-9=7

11x16=176

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7 0
3 years ago
Read 2 more answers
|x + 3| < 5
Elden [556K]

Answer:

<h2>-8 < x < 2</h2>

Step-by-step explanation:

|x+3|

8 0
3 years ago
Which graph represents a function with a rate of change of 0.5? On a coordinate plane, a line with negative slope goes through p
Law Incorporation [45]

Answer:

C

Step-by-step explanation:

I took the test

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5 0
3 years ago
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In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard d
Virty [35]

Answer:

There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

\chi ^{2} = \dfrac{\left (n-1  \right )s^{2}}{\sigma ^{2}}

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,  

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

\chi ^{2} = \dfrac{\left (23-1  \right )950^{2}}{650 ^{2}} = 49.994

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

6 0
3 years ago
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