All categories

3 years ago

Which is larger 589.1 or 58.91

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

6 0

589.1 is 10x bigger.

You might be interested in

Eight identical slips of paper, each containing one number from one to eight, inclusive, are mixed up inside a bag. Subset A of

DochEvi [55]

Answer: The correct option is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: Given that eight identical slips of paper, each containing one number from one to eight, inclusive, are mixed up inside a bag.

The sample space, S will be

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A of the sample space represents the complement of the event in which the number 6 is drawn from the bag.

Let, 'B' represents the event in which the number 6 is drawn from the bag.

So, B = {6}.

Since 'A' is the complement of 'B', so the set 'A' will contain those element of the sample space 'S' that are not in the set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

⇒ A = {1, 2, 3, 4, 5, 7, 8}.

Thus, (C) is the correct option.

7 0

3 years ago

Read 2 more answers

Two rectangles are similar. One has a length of 11 cm and a width of 10 cm, and the other has a width of 7 cm. Find the length o

Alexandra [31]

The answer would be 7.7 cm

4 0

4 years ago

Read 2 more answers

HELP WILL MARK BRainlIEST WITH EXPLANATION

hichkok12 [17]

$Hello$ $There!$

The answer is...

$y=-8x+15.$

HERE'S THE EXPLANATION!

Let's solve for y.

$8x+y=15$

Step 1: Add -8x to both sides.

$8x+y+-8x=15+-8x$

$y=-8x+15$

THE ANSWER!

$y=-8x+15$

Hopefully, this helps you!!

$AnimeVines$

6 0

3 years ago

Hi, need help with solving this logarithm.

vfiekz [6]

Answer:

$\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})$

Step-by-step explanation:

Given

$\log 8 - \log x + 7\log\sqrt x$

Required

Express as a single expression

We have:

$\log 8 - \log x + 7\log\sqrt x$

Write 7 as an exponent

$\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(\sqrt x)^7$

Rewrite as:

$\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(x^{\frac{1}{2}})^7$

$\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log x^\frac{7}{2}$

Apply quotient and product rule of logarithm

$\log 8 - \log x + 7\log\sqrt x =\log (\frac{8*x^\frac{7}{2}}{x} )$

Apply law of indices

$\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7}{2} - 1})$

Solve exponent

$\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7-2}{2}})$

$\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{5}{2}})$

$\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})$

8 0

3 years ago

H U R R Y 2 0 P O I N T S

koban [17]

Distance is 26 hehhehehehehe :)

4 0

4 years ago