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Andreas93 [3]
3 years ago
11

PLEASE HELP WILL GIVE BRAINLIEST

Mathematics
2 answers:
DochEvi [55]3 years ago
8 0
Hello,
Please, see the attached file.
Thanks

Inessa05 [86]3 years ago
6 0
- 10 + SQRT(x + 8) = - 4


Radical Equatiion Entered:

- 10 + SQRT(x + 8) = - 4

Step by step Solution 1:
Isolate the square root on the left hands side.

Original Equation:  
- 10 + SQRT(x + 8) = - 4

Isolate: SQRT(x + 8) = 10 - 4


Tidy up:
SQRT (x + 8) = 6


Step 2: Eliminate the radical on the left hand sied:

Raise both sides to the Second Power:

(SQRT X + 8)^2 = (6)^2


After Squaring
X + 8 = 36


Step 3: Solve Linear equation:

Rearrange Equation:
x - 28 = 0

Add 28 to both sides:
x = 28


Possible solution is:

X = 28


Step 4 CHECK:

Original equation, root isolated, after tidy up.

SQRT(x + 8) = 6

Plug in 28 for X
SQRT(28) + 8 = 6

Simplify:
SQRT(36) = 6


Solution Check is
X = 28

Answer: 
(A.);  X = 28


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HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)
nikitadnepr [17]

Answer:

\frac{x2}{a} - \frac{y2}{b2} = 1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{X2}{16} - \frac{b}{4} = 1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

I don't feel like explaining so...

a. = 4

The foci c is at +/-2√5, using c² = a² + b²:

B = 2

Substituting the value of a and b to get the equation of the hyperbola:

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