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finlep [7]
3 years ago
12

Where do I put the parenthesis in 10+8x5-7+12x2+7=19

Mathematics
2 answers:
Roman55 [17]3 years ago
8 0

Answer: you would put them around the 8 and 5 and around the 12 and 2

Step-by-step explanation:

You do this because in the order of operations you do multiplication first but try out the parentheses to see if they work for this equation

Ludmilka [50]3 years ago
4 0

Answer:

10+(8x5)-7+(12x2)+7=19

Please give Brainliest answer

Step-by-step explanation:

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answer= 2.21 x 10^-10
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What is the area of the area of circle with a circumference of 12.56 feet?
lora16 [44]

Answer:12.56 square units

Step-by-step explanation:

C=2ttr

3 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left
Lisa [10]
1/5 of 20 is $4. so 20-4=$16 remaining
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Answer: $6.07 is the amount ken has remaining
6 0
4 years ago
Read 2 more answers
I need help ASAP. What would go in the middle??
Trava [24]

Answer:

C

Step-by-step explanation:

<h3>7.4 x 10 <em>-3</em>= 0.0074</h3><h3>1.3 x 10 <em>-2</em>= 0.013</h3>

In between them would be 0.0092.

5 0
3 years ago
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