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Yakvenalex [24]

2 years ago

5

For each of the following state whether the given perimeter is possible for a rectangle with an area of 42 Square Units and whol

e number side lengths. if it is possible tell the measurements.
b)46 units
C) 34 units
D) 41 units

1 answer:

givi [52]2 years ago

3 0

My answer is B 46 and thats my answer

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Which equation is graphed along with the parent

snow_lady [41]

Answer:

$g(x) = \sqrt[3]{x - 3 } + 4$

5 0

2 years ago

Read 2 more answers

Demi has 221 songs on her phone. The songs take up 884 megabytes of storage . Each song takes up same amount of space . How many

sveticcg [70]

Answer:

540 megabytes

Step-by-step explanation:

We will first need to find out how much space a<em> singular song</em> will take up. We will do this by <em>the storage taken up (884) by the number of songs she has:</em>

884 / 221 = 4 mb taken up per song

Then we want to find out how many megabytes <em>135 of these songs take up</em>, so we will multiply the <em>mb taken up per song (4) by the number of songs we want to find (135)</em>:

4 x 135 = <em>540 megabytes</em>

<em />

<em>Edit: made a mistake in my original answer, apologies!</em>

7 0

2 years ago

I need help..Please make it correct..

STatiana [176]

Answer:

11/13

Step-by-step explanation:

3/13, 5/13, 7/13, 9/13, <u>11/13</u>

3/13

3/13 + 2/13 = 5/13

5/13 + 2/13 = 7/13

7/13 + 2/13 = 9/13

9/13 + 2/13 = 11/13

4 0

2 years ago

Find the ratio of 4 meter to 50 centimetre

ladessa [460]

(4 meters) / (50 centimeters)

= (4 x 100 centimeters) / (50 centimeters)

= (400 centimeters) / (50 centimeters)

= (400) / (50)

= 8 .

4 0

2 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we <u>do not reject</u> the null hypothesis.
If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we <u>do not reject</u> the null hypothesis.
If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago