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strojnjashka [21]
2 years ago
9

The ratio of the cost of a shirt to the cost of a jacket is 2:5. If the jacket cost $240 more than the shirt,

Mathematics
1 answer:
IrinaVladis [17]2 years ago
6 0

Given:

The ratio of the cost of a shirt to the cost of a jacket is 2:5.

The jacket cost $240 more than the shirt.

To find:

The cost of the shirt and the cost of the jacket.

Solution:

Let x be the cost of the shirt.

The jacket cost $240 more than the shirt. So, the cost of Jacket is (x+240).

The ratio of the cost of a shirt to the cost of a jacket is 2:5. So,

\dfrac{x}{x+240}=\dfrac{2}{5}

5x=2(x+240)

5x=2x+480

Subtract 2x from both sides.

5x-2x=480

3x=480

Divide both sides by 3.

x=\dfrac{480}{3}

x=160

So, the cost of shirt is $160.

Now, the cost of jacket is:

160+240=400

Therefore, the cost of shirt is $160 and the cost of jacket is $400.

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Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

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Answer:

They are 192 km apart.

Step-by-step explanation:

? = unknown value

We can use the equation

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Or ratio

1/8 (What do you multiply 1 by to get to 8? 8. 1 is how many cm there are so if there are 24 cm then we multiply that by 8 as well.)

We have to multiply 24cm by 8 because of the ratio 1:8, 24 times 8 is 192.

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Answer:

a) Given

b) Given

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e) Converse of the Same-side Interior Angles Theorem

Step-by-step explanation:

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