Given:
The ratio of the cost of a shirt to the cost of a jacket is 2:5.
The jacket cost $240 more than the shirt.
To find:
The cost of the shirt and the cost of the jacket.
Solution:
Let x be the cost of the shirt.
The jacket cost $240 more than the shirt. So, the cost of Jacket is (x+240).
The ratio of the cost of a shirt to the cost of a jacket is 2:5. So,
![\dfrac{x}{x+240}=\dfrac{2}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7Bx%2B240%7D%3D%5Cdfrac%7B2%7D%7B5%7D)
![5x=2(x+240)](https://tex.z-dn.net/?f=5x%3D2%28x%2B240%29)
![5x=2x+480](https://tex.z-dn.net/?f=5x%3D2x%2B480)
Subtract 2x from both sides.
![5x-2x=480](https://tex.z-dn.net/?f=5x-2x%3D480)
![3x=480](https://tex.z-dn.net/?f=3x%3D480)
Divide both sides by 3.
![x=\dfrac{480}{3}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B480%7D%7B3%7D)
![x=160](https://tex.z-dn.net/?f=x%3D160)
So, the cost of shirt is $160.
Now, the cost of jacket is:
![160+240=400](https://tex.z-dn.net/?f=160%2B240%3D400)
Therefore, the cost of shirt is $160 and the cost of jacket is $400.