In the point (x, y), if x=0, then the point is on the y axis.
If y=0, the point is on the x axis
If both x and y are positive (greater than 0), the point is in quadrant 1
If x is negative (less than 0) and y is positive (greater than 0), the point is in quadrant 2
If both x and y are negative, the point is in quadrant 3
If x is positive and y is negative, the point is in quadrant 4
Taking (-3, 2), since 3 has a - sign before it (and nothing else), it is negative. Since the x value comes first, this means that x is negative. Since it simply states "2" for the y value, it is positive. As x is negative and y is positive, we know that the point is in quadrant 2.
I challenge you to do this on your own - good luck, and feel free to ask with further questions!
I believe the first on is -1 and the second one is NO SOLUTION
Answer:
{1,4}
Step-by-step explanation:
A={3,6,9}
B={2,3,5,7}
C={1,2,3,4,5}
AUB={2,3,5,6,7,9}
(AUB)'={1,4,8,10}
(AUB)'⋂C={1,4}
(Given)
we find:
, which means the roots of the given quadratic equation are non-real or imaginary.