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3 years ago

Can someone solve this please

Mathematics

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

ML = 6

Step-by-step explanation:

If JM = 6, then ML = 6 because they are congruent.

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Solve by factorising x2 + 8x + 15 = 0

adelina 88 [10]

Answer:

x = - 3/2 thats the answer

6 0

3 years ago

Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1

ivolga24 [154]

Answer:

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

Step-by-step explanation:

We are to factorize the expression $a^{3y} + 1$ completely. To do this, we will apply the expression below;

The expression can be rewritten as $a^{3y} + 1^{3}$

To factorize the expression, we need to first factorize $(a^{y}+1 )^{3}$ first

$(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\$

The we will make $a^{3y} + 1^{3}$ the subject of the formula as shown;

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3} = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

This last result gives the expansion of the expression

7 0

4 years ago

Hi! Can you please help me? I am learning about like terms, and other things. I am kind of confused. Here is an example of what

tigry1 [53]

Your answer is 4z+10

Hope this helps

8 0

3 years ago

Sophia's school has 23 classrooms. Each classroom has 10 tables. How many tables are there in the school?

amid [387]

If there is 23 classrooms and each has 10 then you would have to times 23 by 10 - 23x10=230

4 0

3 years ago

Read 2 more answers

Helppppppppppppppppppppppppppppppppppppppppppppppppp

DENIUS [597]

Answer:

a) 30

b) 88

c) 70

d) 16

e) 160

f) 250

Step-by-step explanation:

So the first step would be to switch the numbers around. For example A would be 15 and 50 instead of the original order of 50 and 15. You would then take the 1st number in the new arranged order (15) and multiply it by 100, then divide in that order. 1500/50 = 30.

Another example, letter B.

Step 1 - Rearrange : 22 and 25

Step 2 - Multiple by 100 = 2200

Step 3 - Divide : 2200/25 = 88

Good Luck :) Hope this helped.

5 0

3 years ago