★ QUADRATIC RESOLUTION ★
Roots of the given equation will be imaginary because it's discriminant is less than 0 and hence it'll yield imaginary solutions
D < 0
b² - 4ac < 0
4² - 4 ( 5 ) < 0
16 - 20 < 0
-4 < 0
Hence it's character is stated above
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Answer:
Step-by-step explanation:
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(See photo for the box and whiskers plot)
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Answer:
1624 units²
Step-by-step explanation:
See attachment for the figure
As, ∠EAB = ∠CFD
and ∠ABE = ∠FCD
We can say that by AA congruency, ΔCFD is similar to ΔBAE
Therefore, BA / EB = CF / DC
BA x DC = EB x CF (since EB = CF
)
BA x DC = EB²
28 x 58 = EB² => area of square BCFE
area of square BCFE = 1624 units²
Therefore, the area of square BCFE is 1624 units²
The answer is X>15 I’m pretty sure