1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DaniilM [7]
3 years ago
10

First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia

l, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material. What is the area of a patch and how many such patches can I make out of the whole material?
Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, \frac{336}{3.728} = 90.37 ≈ 90 such patches can be made out of the whole material. (Answer)

You might be interested in
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
Can someone help me? Thanks!
scZoUnD [109]
3 to the -3 power.. ...
7 0
3 years ago
Read 2 more answers
What is the time that is 9 hours and 40 minutes before 4:25 A.M.
sergey [27]
4:25A.M.-9h=7:25P.M.\ yesterday\\\\40min=25min+15min\\\\7:25P.M.-25min=7:00P.M.\\\\7:00P.M.-15min=\boxed{6:45P.M.\ yesterday}
4 0
3 years ago
Read 2 more answers
Help with 3 short questions
quester [9]
Sorry I have no idea
4 0
3 years ago
Read 2 more answers
Geometry- You are designing a poster that will be 3yd wide and 8ft high. How much paper do you need to make the poster? Give you
Sav [38]
Yea. The text book is either wrong or it knows something that we don't. Like as to why they would need to have two more feet. You're right though
6 0
3 years ago
Other questions:
  • The leader of the team wants to do everything him or herself. They have a very big ego and are difficult to work with. What is t
    14·1 answer
  • ¿cuantos metros de cerca se necesita para un terreno rectangular que tiene 104 metros de largo y cuyo ancho mide 76 metros menos
    15·1 answer
  • If f(x) = 2x squared -30 find f(4)
    9·2 answers
  • * ANSWER PLS TY!! * Find the surface area of this cone.
    7·1 answer
  • What is the decimal form of -4 7/8
    6·1 answer
  • Which expression is equivalent to t2 – 36?
    11·1 answer
  • Kianna started her homework at 4:30 pm. She finished at 5:05 pm. How many SECONDS did it take her to finish her homework? *
    8·2 answers
  • Please just find the measures of the segment plzzzzzzzz
    7·1 answer
  • -. Find the value of x. Round to the nearest degree.
    10·1 answer
  • Value of x here is ????<br><br><br><img src="https://tex.z-dn.net/?f=30x%20%3D%2015%20%2B%2015" id="TexFormula1" title="30x = 15
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!