Answer:
Hi my friend! The correct answer to this question is D.
Explanation:
The student was right assuming that 27 its nos a perfect square, so, the association between 25 and 36 its possible. If you check with a calculator, you will see that the result is 5.19, wich is approxim. 5.2.
<u>Answer:</u> The mass of iron (III) nitrate is 11.16 g/mol
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.3556 M
Molar mass of Iron (III) nitrate = 241.86 g/mol
Volume of solution = 129.8 mL
Putting values in above equation, we get:
Hence, the mass of iron (III) nitrate is 11.16 g/mol
Answer:
They break down materials into smaller pieces
Explanation:
Although using different methods
2.5 * 1/2.2 * 1000 = 1136 g
OR
2.5 * 454 = 1135 g
You can use either for your conversion.
Answer:
Structure 1 formal charges:
N₁ = +1; O₁₁ = +1; O₁₂ = -1; N₂ = 0; N₃ = +1; O₃₁ = -1; O₃₂ = -1
Structure 2 formal charges:
N₁ = +1; O₁₁ = +1; O₁₂ = -1; N₂ = -1; N₃ = +1; O₃₁ = -1; O₃₂ = +1
Structure 3 formal charges:
N₁ = +1; O₁₁ = -1; O₁₂ = -1; N₂ = +1; N₃ = +1; 0₃₁ = -1; O₃₂ = -1
Explanation:
The formal charge of an atom in a molecule is the charge assigned to the atom if the electrons in all chemical bonds were redistributed evenly between the atoms.
Formal charge can be calculated as follows:
Formal charge = number of valence shell electrons in the neutral atom − ( number of lone pair electrons + ½ bonding electrons)
Structure 1:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 5 = +1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 5= 0
N₃ = 5 - 4 = +1
O₃₁ = 6 - 7 = -1
O₃₂ = 6 - 7 = -1
Structure 2:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 5 = +1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 6= -1
N₃ = 5 - 4 = +1
O₃₁ = 6 - 7 = -1
O₃₂ = 6 - 5 = +1
Structure 3:
N₁ = 5 - 4 = +1
O₁₁ = 6 - 7 = -1
O₁₂ = 6 - 7 = -1
N₂ = 5 - 4 = +1
N₃ = 5 - 4 = +1
0₃₁ = 6 - 7 = -1
O₃₂ = 6 - 7 = -1