Answer:
[KOH] : 1.47 M
[KOH] : 1.22 m
[KOH]: 6.42 % mass percent.
Explanation:
First of all we must determine the volume of solution. We have to work with the density
Density = mass / volume
1.29 g/ml = mass / 1870 ml
1.29 g/ml . 1870 ml = 2412.3
Now we must convert the mass to moles
155g / 56.1 g/ mol = 2.76 moles
Now we can calculate molarity
2.76 mol / 1.87 L = 1.47 M
To calculate molality we have to find out the mass of solvent
mass solute + mass solvent = mass solution
155 g + mass solvent = 2412.3 g
2412.3g - 155g = 2257.3g
We have to convert the 2257.3 g to kg
2257.3 g = 2.25 kg
molality = 2.76 moles / 2.25 kg = 1.22 m
To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.
In 2412.3 g of solution we have 155 g of KOH
In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.
