1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bixtya [17]
3 years ago
5

At 0°c a bottle contains a 325 mL of water in its liquid state. What is the volume of the water after it freezes (at 0°C)?

Chemistry
1 answer:
Semmy [17]3 years ago
5 0

Answer:

The volume of the water after it freezes (at 0°C) is 354.4 mL.

Explanation:

We need to use this additional information, the densities of liquid water and ice at 0 °C are 1.000 g/mL and 0.917 g/mL, respectively.

Step 1. Find the mass of water before it freezes.

325 \:mL \cdot 1.000 \:{\frac{g}{mL} }=325 \:g

Step 2. The mass does not change when the temperature does. So, you take the grams of water and divide it by the density of the ice to obtain the volume it occupies.

325 \:g\cdot \frac{1}{0.917 \:{\frac{g}{mL} }} =354.4 \:mL

You might be interested in
What volume (L) will 3.56 mol NH3 occupy at STP. (1 point)
mart [117]

Answer:

B

Explanation:

I hope it helps you good luck

7 0
3 years ago
Draw the structure of a compound with the molecular formula CgH1002 that exhibits the following spectral data.
Gnesinka [82]

Answer:

The answer you are looking for is A

7 0
3 years ago
A 4.24 kg marble slab has the volume of 1564 cm3 What is the density in g/cm3
miskamm [114]

Answer:

The answer is

<h2>2.71 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

volume of marble = 1564 cm³

1 kg = 1000 g

4.24 kg = 4240 g

mass = 4240 g

The density is

density =  \frac{4240}{1564}   \\  = 2.710997442...

We have the final answer as

<h3>2.71 g/cm³</h3>

Hope this helps you

7 0
3 years ago
Can someone please help me with this?
yaroslaw [1]

Answer:

Lonic.an electron will be transferred from potassium to the chlorine atom

3 0
3 years ago
Read 2 more answers
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

3 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the root mean square velocity of F2,Cl2, and Br2 at 304 K .
    6·1 answer
  • Calculate the mass in grams of a single atom C¹²​
    7·2 answers
  • Select all that apply.
    10·1 answer
  • What's a metaloid, science
    11·1 answer
  • Specify which atoms, if any, bear a formal charge in the Lewis structure given and the net charge for the species. Be sure to an
    13·1 answer
  • 4. One mole of oxygen contains 6.02 x 102 molecules. How many oxygen molecules are in
    11·1 answer
  • Plz answer this i will mark brainly like and ratr
    15·1 answer
  • What is X ? <br> A-ethanol <br> B-hydrogen<br> c-methane<br> D-uranium
    13·2 answers
  • what the greatest agent of change?water/wind/ice how does this agent continue to weathering lake annette
    5·1 answer
  • If a 10.0ml sample of unknown liquid has a mass of 7.553g what is the density of the unknown liquid
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!