At 0°c a bottle contains a 325 mL of water in its liquid state. What is the volume of the water after it freezes (at 0°C)?
1 answer:
Answer:
The volume of the water after it freezes (at 0°C) is 354.4 mL.
Explanation:
We need to use this additional information, the densities of liquid water and ice at 0 °C are 1.000 g/mL and 0.917 g/mL, respectively.
Step 1. Find the mass of water before it freezes.
Step 2. The mass does not change when the temperature does. So, you take the grams of water and divide it by the density of the ice to obtain the volume it occupies.
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Answer:
21.6 g
Explanation:
The reaction that takes place is:
- CH₄ + 2O₂ → CO₂ + 2H₂O
First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:
- 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
- 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂
0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.
Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:
- 0.6 mol CH₄ *
= 1.2 mol H₂O
Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:
- 1.2 mol * 18 g/mol = 21.6 g