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Ymorist [56]
3 years ago
14

Rewrite and Balance the Equation N₂ + H₂ -> NH3

Chemistry
2 answers:
snow_lady [41]3 years ago
5 0

Answer:

you said brainliest

Explanation:

Mars2501 [29]3 years ago
4 0

Answer:N

2

+ 3

H

2

-----> 2N

H

3

Explanation:

N

2

+

H

2

-----> N

H

3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N

2

+

H

2

-----> N

H

3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H

3

on RHS

N

2

+

H

2

-----> 2N

H

3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H

2

on LHS

N

2

+ 3

H

2

-----> 2N

H

3

N=2 , H=6 N=2 , H= 6

Answer link

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Determine the percent ionization of a 0.225 M solution of benzoic acid. Express your answer using two significant figures.
Assoli18 [71]

Answer:

1.68% is ionized

Explanation:

The Ka of benzoic acid, C₇H₆O₂, is 6.46x10⁻⁵, the equilibrium in water of this acid is:

C₇H₆O₂(aq) + H₂O(l) ⇄ C₇H₅O₂⁻(aq) + H₃O⁺(aq)

Ka = 6.46x10⁻⁵ = [C₇H₅O₂⁻] [H₃O⁺] / [C₇H₆O₂]

<em>Where [] are concentrations in equilibrium</em>

In equilibrium, some 0.225M of the acid will react producing both C₇H₅O₂⁻ and H₃O⁺, the equilibrium concentrations are:

[C₇H₆O₂] = 0.225-X

[C₇H₅O₂⁻] = X

[H₃O⁺] = X

Replacing:

6.46x10⁻⁵ = [X] [X] / [0.225-X]

1.4535x10⁻⁵ - 6.46x10⁻⁵X = X²

1.4535x10⁻⁵ - 6.46x10⁻⁵X - X² = 0

Solving for X:

X = -0.0038. False solution, there is no negative concentrations.

X = 0.00378M. Right solution.

That means percent ionization (100 times Amount of benzoic acid ionized  over the initial concentration of the acid) is:

0.00378M / 0.225M * 100 =

<h3>1.68% is ionized</h3>
8 0
3 years ago
This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water.
ryzh [129]

Complete Question:

This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water. Using the formula V M D = , what is the density of the marble?

(See attachment for full diagram)

Answer:

1.27 g/cm³

Explanation:

First, find the volume of rock:

Volume of rock = volume of water after rock was placed - volume of water before rock was placed

Volume of rock = 13 - 10 = 3ml

Density of rock = grams of rock per 1 cm³

Note: 1 ml = 1 cm³

Let x represent amount of rock per 1 cm³

Thus,

3.8g = 3 cm³

x = 1 cm³

Cross multiply

1*3.8 = 3*x

3.8 = 3x

3.8/3 = 3x/3

1.27 = x

Density of rock = 1.27 g/cm³

3 0
3 years ago
Gas is $2.50/gal at Station A and 85 cents/L at Station B. A) Convert the cost of gas at Station B to $/gal. B) At which station
SVETLANKA909090 [29]

Answer:

85 cents/L is equal to 3.2176$/gallon.

gas wiuld be heaper to buy from the station A.

Explanation:

As 85 cents/L is more than $2.5/gallon therefore buying gas from station A would be cheaper than the other one.

8 0
3 years ago
How do scientists describe the behavior of particles in solids and plasmas?
blondinia [14]

Answer:

The properties of a solid are that they form at a low temperature, particles have long range order meaning that the particles are fixed in place, the particles have a defined shape and volume, the solid particles are a low-energy state of matter, and solid particles are dense and incompressible. But on the other hand plasma particles form at high temperatures, plasma particles have short range order meaning that the plasma particles have little interaction, plasma particles fill all available space meaning plasma particles have no fixed shape or volume, plasma particles are the highest energy-state of matter, plasma particles are highly compressible, and plasma particles conduct electricity extremely well.

Explanation:

8 0
3 years ago
Enter the Ksp expression for the solid AB2 in terms of the molar solubility x. AB2 has a molar solubility of 3.72×10−4 M. What i
AlekseyPX

Answer:

2.06 × 10⁻¹⁰

Explanation:

Let's consider the solution of a generic compound AB₂.

AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

We can relate the molar solubility (S) with the solubility product constant (Kps) using an ICE chart.

      AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

I                      0              0

C                    +S            +2S

E                      S              2S

The solubility product constant is:

Kps = [A²⁺] × [B⁻]² = S × (2S)² = 4 × S³ = 4 × (3.72 × 10⁻⁴)³ = 2.06 × 10⁻¹⁰

5 0
3 years ago
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