The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.
The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.
![\begin{gathered} 4y-2=90 \\ 4y=92 \\ y=23 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204y-2%3D90%20%5C%5C%204y%3D92%20%5C%5C%20y%3D23%20%5Cend%7Bgathered%7D)
The value of y is 23.
The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.
![\begin{gathered} 3x=45 \\ x=15 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203x%3D45%20%5C%5C%20x%3D15%20%5Cend%7Bgathered%7D)
Thus, the value of x is 15 degrees.
The value of 12z is 45 degrees.
![\begin{gathered} 12z=45 \\ z=3.75 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2012z%3D45%20%5C%5C%20z%3D3.75%20%5Cend%7Bgathered%7D)
Thus, the required value of z is 3.75 degrees.
Answer:
$6
Step-by-step explanation:
let x and y be the number of chip and pretzel bags respectively :
4x%2B2y%3 C=20
:
if x=1 then 4%281%29%2B2y%3C=20--->{{2y<=16}}}--->y%3C=8 :
if x=3 then 4%283%29%2B2y%3C=20--->{{2y<=8}}}--->y%3C=4 :
so chips 1 and pretzels 8 :
chips 3 and pretzels 4.
Answer:
f(x-3)= x^2 -11x +24
Step-by-step explanation:
We want to find an equivalent expression for f(x-3)
To do this, we can simply substitute every 'x' variable in f(x) by 'x-3'
Therefore f(x-3)= (x-3)^2 -5*(x-3)
Lets re arrange the expression by grouping terms.
f(x-3)=x^2 - 6x +9 -5x + 15
f(x-3)= x^2 -11x +24
De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.
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- En el sistema de ecuaciones, tiene-se que los números son x e y.
- Suma de 115, o sea,
![x + y = 115](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%20115)
- <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea,
![x = 2y + 22](https://tex.z-dn.net/?f=x%20%3D%202y%20%2B%2022)
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Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>
![x + y = 115](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%20115)
![2y + 22 + y = 115](https://tex.z-dn.net/?f=2y%20%2B%2022%20%2B%20y%20%3D%20115)
![3y = 93](https://tex.z-dn.net/?f=3y%20%3D%2093)
![y = \frac{93}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B93%7D%7B3%7D)
![y = 31](https://tex.z-dn.net/?f=y%20%3D%2031)
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El número mayor es dado en <u>función de el menor</u>, o sea:
![x = 2y + 22 = 2(31) + 22 = 62 + 22 = 84](https://tex.z-dn.net/?f=x%20%3D%202y%20%2B%2022%20%3D%202%2831%29%20%2B%2022%20%3D%2062%20%2B%2022%20%3D%2084)
Los números son 31 y 84.
Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096
For lines to be parallel, they have to have the same slopes. For the equation given as Ax + By + C = 0, the slope is -A / B. Equating the slopes of the given equations of lines,
- (3 / -5) = - (2 / k)
The value of k is equal to -10/3.