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sergij07 [2.7K]
3 years ago
12

Find the zeros of the function. f(x) = 3x2 – 8x – 16

Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

amusing you mean 3x^2-8x-16 the answer is when x is equal to -4/3 and 4

Step-by-step explanation:

3x^2-8x-16 ------> (3x+4)(x-4)

3x+4=0 ----> 3x=-4 ----> x=-4/3

x-4=0 ----> x=4

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PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
Name the side of the triangle that is opposite angle A *<br> Captionless Image<br> AB<br> AC<br> BC
Olenka [21]

Answer:

BC

Step-by-step explanation:

because it is what it is

7 0
3 years ago
Use the remainder theorem to determine if x = 2 is a zero of the following polynomial, and find the quotient and the remainder.
Fofino [41]

Answer:

(A) Yes, x = 2 is a zero of the polynomial.

The quotient is x² + 26x + 160 and the remainder is 0

Step-by-step explanation:

Given;

p(x) = x³ + 24x² + 108x - 320

Using remainder theorem to test if x = 2 is a zero of the given function

p(2) = (2)³ + 24(2)² + 108(2) - 320

       = 8 + 96 + 216 - 320

        = 0

Thus, x = 2 is zero of the function

(ii) to get the quotient and the remainder of the given function, divide the function by 'x - 2'

                     x² + 26x + 160

     x - 2    √ x³ + 24x² + 108x - 320

                 -  (x³ -  2x²)                      

                     0   + 26x² + 108x - 320

                          - (26x²  - 52x)                  

                               0      + 160x - 320

                                        -  (160x - 320)        

                                              0     +   0  

The quotient is x² + 26x + 160

The remainder is 0                      

                                                 

Thus, the correct option is A.

Yes, x = 2 is a zero of the polynomial.

The quotient is x² + 26x + 160 and the remainder is 0            

3 0
3 years ago
What is x? Can you please help?
Goryan [66]

Answer:

The answer to your question is: x = 2

Step-by-step explanation:

Data

LM = 6x

MN = 10x + 4

LN = 20x - 4

x = ?

Process

                     LM + MN = LN

Then

                                 6x + 10x + 4 = 20x - 4

Solve for x               16x + 4 = 20x -4

                                16x - 20x = -4 - 4

                               -4x = -8

                                x = -8/-4

                               x = 2

                               6(2) + 10(2) + 4 = 20(2) - 4    

                              12 + 20 + 4 = 40 -4

                              36 = 36

4 0
3 years ago
HELP ASAP AGAIN (FIXED)!!!!!!!
larisa [96]

Answer:

help with what

Step-by-step explanation:

can you kindly give me brainliest i need this for Expert rank

7 0
3 years ago
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