Answer:
1.71 × 10²¹ molecules
Explanation:
1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:
500 mg × (1 g / 1000 mg) = 0.500 g
The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:
0.500 g × (1 mol/ 176.12 g) = 0.00284 mol
In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:
0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule
Answer:
18. E. 0%
19. D. 25%
Explanation:
Question 18:
Let's use "B" to represent the dominant allele of "light blue skin", and
"b" for recessive "light green skin".
Squidward => BB - light blue skin
Squidward's bride => bb - light green skin
When they cross, they will have the following offsprings:
(BB) × (bb) - Parent
(Bb) (Bb) (Bb) (Bb) - Offspring
All the offspring would be light green skin. The dominant allele of light green skin will express itself over the recessive allele.
Therefore, the chances of Squidward and his bride having light green skin is 0%
Question 19:
Squidward's son => Bb - light blue skin
Squidward's son's bride => Bb - light blue skin
(Bb) × (Bb) - parent
(BB) (Bb) (Bb) (bb) - offspring
They will have the following offspring:
BB and Bb - light blue - 75%
bb - light green - 25%
Chance of having offspring with light green skin is 25%
Answer: longhand notation
Explanation: I just did it on Edg
Answer:
I would expect ig to be polar
Explanation:
because it can not be nonpolor.
Answer:
pKa = 4.89.
Explanation:
We can solve this problem by using the <em>Henderson-Hasselbach equation</em>, which states:
pH = pKa + log
In this case [A⁻] is the concentration of sodium benzoate and [HA] is the concentration of benzoic acid.
We <u>input the given data</u>:
4.63 = pKa + log
And <u>solve for pKa</u>:
pKa = 4.89