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3 years ago

If f(x) = 2x2 − 10, find f(5). 90 10 7.5 40

2 answers:

8 0

If you mean 2x^2 (squared) - 10, then all you have to do is replace x with 5.

f(5) = 2(5)^2 - 10
= 2 (25) - 10
= 50 - 10
f(5) = 40

MatroZZZ [7]3 years ago

5 0

F(x)= 2x² -10
f(5)= 2(5)²-10

f(5)= 40

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Answer:

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Step-by-step explanation:

Given

$10x + 4y < 12$

$8x - 3y > 20$

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

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$30 - 32 < 12$

$-2 < 12$ --- True

$8x - 3y > 20$

$8 * 3 - 3 * -8> 20$

$24 +24> 20$

$48> 20$ --- True

(2, 5)

x = 2 and y = 5

$10x + 4y < 12$

$10 * 2 + 4 * 5 < 12$

$20 + 20 < 12$

$40 < 12$ --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

$10x + 4y < 12$

$10 * -5 + 4 * 1 < 12$

$-46 < 12$ --- True

$8x - 3y > 20$

$8 * -5 - 3 * 1 > 20$

$-43 > 20$ --- False

(10, 3)

x = 10 and y = 3

$10x + 4y < 12$

$10 * 10 + 4 * 3 < 12$

$112 < 12$ --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

$10x + 4y < 12$

$10 * 2 + 4 * -10 < 12$

$-20 < 12$ --- True

$8x - 3y > 20$

$8 * 2 - 3 * -10 > 20$

$46 > 20$ --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

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