<span>(3, 4.5) and (3, 3)
The midsegment of a triangle is a line connecting the midpoints of two sides of the triangle. So a triangle has 3 midsegments. Since you want the midsegment that's parallel to LN, we need to select the midpoints of LM and MN. The midpoint of a line segment is simply the average of the coordinates of each end point of the line segment. So:
Midpoint LM:
((0+6)/2, (5+4)/2) = (6/2, 9/2) = (3, 4.5)
Midpoint MN:
((6+0)/2, (4+2)/2) = (6/2, 6/2) = (3, 3)
So the desired end points are (3, 4.5) and (3, 3)</span>
Answer:
Step-by-step explanation:

Answer:
- hemisphere volume: 262 m³
- cylinder volume: 942 m³
- composite figure volume: 1204 m³
Step-by-step explanation:
A. The formula for the volume of a hemisphere is ...
V = (2/3)πr³
For a radius of 5 m, the volume is ...
V = (2/3)π(5 m)³ = 250π/3 m³ ≈ 261.799 m³
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B. The formula for the volume of a cylinder is ...
V = πr²h
For a radius of 5 m and a height of 12 m, the volume is ...
V = π(5 m)²(12 m) = 300π m³ ≈ 942.478 m³
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C. Then the total volume is ...
V = hemisphere volume + cylinder volume
V = 261.799 m³ +942.478 m³ = 1204.277 m³
__
Rounded to the nearest integer, the volumes are ...
- hemisphere volume: 262 m³
- cylinder volume: 942 m³
- composite figure volume: 1204 m³
_____
As a rule, you only want to round the final answers. Here, the numbers are such that rounding the intermediate values still gives the correct final answer. That is not always the case.
<span>The probability, or expectation value for X in a block, equals the number of occurrences of X in all the blocks divided by the total number of blocks
</span>
well E(X)=µ
and
Var(X)=E[(X-µ)^2]
Answer:
are you ok?
Step-by-step explanation:
why did you need help lol