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denis23 [38]
3 years ago
6

Write a quadratic function in vertex form whose graph has the vertex

Mathematics
1 answer:
ELEN [110]3 years ago
4 0

Answer:

y = \frac{1}{2}(x - 5)² - 2

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (5, - 2), thus

y = a(x - 5)² - 2

To find a substitute (7, 0) into the equation

0 = a(7 - 5)² - 2

0 = 4a - 2 ( add 2 to both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{2}{4} = \frac{1}{2}

y = \frac{1}{2} (x - 5)² - 2 ← in vertex form

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<span>(3, 4.5) and (3, 3)

       The midsegment of a triangle is a line connecting the midpoints of two sides of the triangle. So a triangle has 3 midsegments. Since you want the midsegment that's parallel to LN, we need to select the midpoints of LM and MN. The midpoint of a line segment is simply the average of the coordinates of each end point of the line segment. So:

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Answer:

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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