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slamgirl [31]
3 years ago
12

Find the coordinate of K' after a Glide reflection of the triangle: translation 4 units up and 4 units right then a reflection a

cross the line y = 1.
Part 3a​

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

  a.  (-1, 3)

Step-by-step explanation:

The "glide" 4 units right and up is the transformation ...

  (x, y) ⇒ (x+4, y+4)

The reflection across y=1 is the transformation ...

  (x, y) ⇒ (x, 2-y)

Combined, you have the transformation ...

  (x, y) ⇒ (x +4, 2-(y +4)) = (x +4, -2-y)

Then, ...

  K(-5, -5) ⇒ K'(-5 +4, -2-(-5)) = K'(-1, 3)

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antoniya [11.8K]

Answer:

A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

Step-by-step explanation:

<u>Step 1:  Determine the sides</u>

A → 3 ft

B → 7 ft

C → 4 ft

D → 5 ft

<u>Step 2:  Determine the surface area</u>

Area of the sides

A= 4\ ft * 7\ ft = 28\ ft^2

A= 5\ ft * 7\ ft = 35\ ft^2

A= 3\ ft * 7\ ft = 21\ ft^2

Area of the top and bottom triangles

A= \frac{h\ *\ b}{2} = \frac{3\ ft\ *\ 4\ ft}{2} = \frac{12\ ft^2}{2} = 6\ ft^2 = 2(6\ ft^2) = 12\ ft^2

Total Area

28\ ft^2 + 35\ ft^2 + 21\ ft^2 + 12\ ft^2

96\ ft^2

Answer:  A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

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2 years ago
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nasty-shy [4]
It's 85 degrees. Hope this helps
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3 years ago
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3 years ago
Please help me with this math question​
scZoUnD [109]

Answer:

<h2>d : e : f = 4 : 3 : 6</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}

\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.

\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}

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I would do 3+5 so then it equals 8
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