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Schach [20]
3 years ago
8

Can some one please explain this? Thank you all!

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0
Basically bill wrote or chose a number. That number that he chose needed to have 2 things.

1. It needed to have been a number in between 27 and 45

2. It needed to have been an odd number in between 27 and 45.

There are only 2 possible choices that are odd, so eliminate the other 2 that are even. Next look at the 2 numbers that are odd.

The digits for each number must add up to 8.

35 - 3 + 5 = 8
43 - 4 + 3 = 7.

Which number adds up to 8. The digits in 35 or 43? It is 35.

Thus the final solution is 35. The number that Bill wrote.
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Three Texas drovers met on a highway and began to dicker as follows:
Alik [6]

Answer:

  • Jim's: 7
  • Duke's: 21
  • Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

  2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

  3(D -14 +1) = (H +14 -1) . . . . Duke's offer

  6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

  2H - J = 15

  3D - H = 52

  6J - D = 21

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<u>Solution</u>

Adding twice the second equation to the first gives ...

  2(3D -H) +(2H -J) = 2(52) +(15)

  6D -J = 119

Adding 6 times the third equation to this one gives ...

  6(6J -D) +(6D -J) = 6(21) +(119)

  35J = 245

  J = 7

Using this value in the third equation gives ...

  6(7) -D = 21

  42 -21 = D = 21

Using the value of J in the first equation gives ...

  2H -7 = 15

  H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

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3 years ago
Which two linear equations represent perpendicular lines? select two choices?
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Let's take y = x + b and y = -x + b
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