An element has a shiny metallic appearance and is both ductile and malleable. In which section of the diagram would the element
most likely be found?
A.
1.
B.
2.
C.
3
D.
4
A.
1.
B.
2.
C.
3
D.
4
1 answer:
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Answer : The Lewis-dot structure for the following molecules are shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
Now we have to determine the Lewis-dot structure for the following molecules.
(a) The given molecule is,
As we know that iodine and chlorine have '7' valence electrons.
Therefore, the total number of valence electrons in = 7 + 7 = 14
According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.
(b) The given molecule is,
As we know that phosphorous has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(c) The given molecule is,
As we know that phosphorous has '5' valence electrons.
Therefore, the total number of valence electrons in = 4(5) = 20
According to Lewis-dot structure, there are 6 number of bonding electrons and 14 number of non-bonding electrons.
(d) The given molecule is,
As we know that sulfur has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 6 + 2(1) = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
(e) The given molecule is,
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 2(5) + 4(1) = 14
According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.
(f) The given molecule is,
As we know that chlorine has '7' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 1 + 7 + 3(6) = 26
According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.
(g) The given molecule is,
As we know that bromine has '7' valence electrons, oxygen has '6' valence electrons and carbon has '4' valence electrons.
Therefore, the total number of valence electrons in = 4 + 6 + 2(7) = 24
According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.
