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In-s [12.5K]
3 years ago
13

Which of the following dienes would you expect to be the most stable? CH3CH2CH=CHCH2CH=CHCH3 CH3CH=CHCH=CHCH2CH3 CH2=CHCH2CH2CH2

CH=CH2 CH2=CHCH=CHCH2CH2CH3 CH3CH=C(CH3)CH=CHCH2CH3
Chemistry
1 answer:
saveliy_v [14]3 years ago
4 0

Answer:

CH3CH=C(CH3)CH=CHCH2CH3

Explanation:

This question is all about determining the stability for Dienes. Dienes are divided into three major parts that is the cumulated diene, Isolated dienes, and conjugated dienes.

Among the three types or classes of dienes, the conjugated type of diene is the most stable. That is to say that among the five compounds given in the question the most stable is CH3CH=C(CH3)CH=CHCH2CH3 which is a conjugated diene.

The reason behind the stability of this compound, that is CH3CH=C(CH3)CH=CHCH2CH3 is because of what is known as delocalization . Hybridization and Resonance are what causes the delocalization which involves pie interactions with alpha hydrogen, also, another reason behind the stability is the lower heat of hydrogenation.

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Answer:

1.346 v

Explanation:

1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

(oxidation) Cu_{(s)} →Cu^{2+}_{(aq)} +2e E°=0.337 v

(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

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