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frez [133]
3 years ago
6

Why does calcium conduct electricity?

Chemistry
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

calcium is a metal and metals are good conductors of electricity as they contain mobile electrons.

Explanation:

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What can you infer about particle's size?
gayaneshka [121]

Answer:

particle size analysis, particle size measurement, or simply particle sizing is the collective name of the technical procedures, or laboratory techniques which determines the size range, and/or the average, or mean size of the particles in a powder or liquid sample.

Explanation:

8 0
3 years ago
Can someone please help me
Vanyuwa [196]

Answer:

1.7

Explanation:

Density = M/V

When you divide 4.52 by 2.6, you get 1.738461538, which can be simplified to 1.7.

7 0
3 years ago
A solution of Na2CO3 is added dropwise to a solution that contains 1.15×10−2 M Fe2+ and 0.58×10−2 M Cd2+. What concentration of
castortr0y [4]

The question is incomplete, complete question is;

A solution of Na_2CO_3 is added dropwise to a solution that contains1.15\times 10^{-2} M of Fe^{2+} and 0.58\times 10^{-2} M and Cd^{2+}.

What concentration of CO_3^{2-} is need to initiate precipitation? Neglect any volume changes during the addition.

K_{sp} value FeCO_3: 2.10\times 10^{-11}

K_{sp} value CdCO_3: 1.80\times 10^{-14}

What concentration of CO_3^{2-} is need to initiate precipitation of the first ion.

Answer:

Cadmium carbonate will precipitate out first.

Concentration of CO_3^{2-} is need to initiate precipitation of the cadmium (II) ion is 3.103\times 10^{-12} M.

Explanation:

1) FeCO_3\rightleftharpoons Fe^{2+}+CO_3^{2-}

The expression of an solubility product of iron(II) carbonate :

K_{sp}=[Fe^{2+}][CO_3^{2-}]

2.10\times 10^{-11}=0.58\times 10^{-2} M\times [CO_3^{2-}]

[CO_3^{2-}]=\frac{2.10\times 10^{-11}}{1.15\times 10^{-2} M}

[CO_3^{2-}]=1.826\times 10^{-9}M

2) CdCO_3\rightleftharpoons Cd^{2+}+CO_3^{2-}

The expression of an solubility product of cadmium(II) carbonate :

K_{sp}=[Cd^{2+}][CO_3^{2-}]

1.80\times 10^{-14}=0.58\times 10^{-2} M\times [CO_3^{2-}]

[CO_3^{2-}]=\frac{1.80\times 10^{-14}}{0.58\times 10^{-2} M}

[CO_3^{2-}]=3.103\times 10^{-12} M

On comparing the concentrations of carbonate ions for both metallic ions, we can see that concentration to precipitate out the cadmium (II) carbonate from the solution is less than concentration to precipitate out the iron (II) carbonate from the solution.

So, cadmium carbonate will precipitate out first.

And the concentration of carbonate ions to start the precipitation of cadmium carbonate we will need concentration of carbonate ions greater than the 3.103\times 10^{-12} M concentration.

6 0
3 years ago
Please help!
Grace [21]
The most common reaction that causes spoilage isn't a reaction at all. Molds and Bacteria are attracted to the easily found presence of water in the fruit. They find a natural place to reproduce and what they do causes spoilage.

Very few sources talk about the chemical changes that take place. If you put fruit in a refrigerator it slows the spoiling process down. That means that the chemical reaction has to be endothermic (it requires heat to occur)

The process of spoilage is speeded up by bananas for example, giving up Ethylene gas. You do not want to put a banana with tomatoes, because tomatoes are very sensitive to Ethylene. (It's OK to eat them together. They make a terrific salad. Yum).

I cannot find a definitive source that connects all this together, but the conduct of the fruit in refrigerators confirms what I am saying.

Spoilage is a very complex reaction and interaction with the environment. I have given you a hint of what happens but you should search it out to convince yourself of the outcome.
3 0
3 years ago
Help, 8th grade Science
valentinak56 [21]

Answer:

Control container

Explanation:

5 0
3 years ago
Read 2 more answers
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